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belka [17]
3 years ago
10

Explain why neon is monatomic but chlorine is diatomic.

Chemistry
2 answers:
Elza [17]3 years ago
5 0
Chlorine is a halogen and all halogens and oxygen, nitrogen and hydrogen are diatomics
kirza4 [7]3 years ago
4 0

Explanation:

Neon is in group 8/0, which means that it has a full outer shell. Atoms react to get a full outer shell but as neon already has a full outer shell, it doesn't react and stays monatomic.

However, chlorine is in group 7, so it needs 1 more electron to complete its outer shell, two chlorine atom share one electron each with each other so they have full outer shells. This is why chlorine is diatomic.

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An unknown amount of acid can often be determined by adding an excess of base and then back-titrating the excess. A 0.3471−g sam
MAXImum [283]

Explanation:

The given data is as follows.

       Mass of mixture = 0.3471 g

As the mixture contains oxalic acid and benzoic acid. So, oxalic acid will have two protons and benzoic acid has one proton.

This means oxalic acid will react with 2 moles of NaOH and benzoic acid will react with 1 mole of NaOH.

Hence,   moles of NaOH in 97 ml = \frac{0.1090 \times 97}{1000}

                                                       = 10.573 \times 10^{-3} mol

Moles of HCl in 21.00 ml = \frac{0.2060 \times 21}{1000}

                                         = 4.326 \times 10^{-3} mol

Therefore, total moles of NaOH that reacted are as follows.

           10.573 \times 10^{-3} mol - 4.326 \times 10^{-3} mol      

                = 6.247 \times 10^{-3} mol

So, total 3 mole of NaOH will react with 1 mole of mixture. Therefore, number of moles of NaOH reacted with benzoic acid is as follows.

                  \frac{6.247 \times 10^{-3}}{3}

                    = 2.082 \times 10^{-3} mol

Since, molar mass of NaOH is 40 g/mol. Therefore, calculate the mass of NaOH as follows.

                    2.082 \times 10^{-3} mol \times 40 g/mol

                         = 83.293 \times 10^{-3} g

                         = 0.0832 g

Whereas molar mass of benzoic acid is 122 g/mol.

Therefore,       40 g NaOH = 122 g benzoic acid

So,            0.0832 g NaOH = \frac{122 g}{40 g} \times 0.0832 g

                                             = 0.253 g

Hence, calculate the % mass of benzoic acid as follows.

                      \frac{0.253 g}{0.3471 g} \times 100

                           = 73.10%

Thus, we can conclude that mass % of benzoic acid is 73.10%.

4 0
3 years ago
How do trends in the periodic table help predict the properties of an element
irina1246 [14]
As you move around there is a change in: electronegativies, ionisation energies, atomic radius etc. different amounts of these properties are going to effect how the element acts
8 0
3 years ago
What are the effects of inhalation of acetone vapor?
Ipatiy [6.2K]

Answer:

it can cause irritation in eyes throat and lungs and u can become lightheaded, or possibly fall in a coma

5 0
3 years ago
An enclosed vessel contains 2.5g of 9b nitrogen and 13.3g of chlorine at s.T.P. Of What will be the partial pressure of the Il n
kow [346]

Answer:

0.535 atm

Explanation:

Since the volume of the tank is constant, we use Gay- Lussac's law to find the pressure at 180°C.

So, P₁/T₁ = P₂/T₂ where P₁ = pressure at S.T.P = 1 atm, T₁ = temperature at S.T.P = 273.15 K, P₂ = pressure of gas at 180 °C and T₂ = 180 °C = 273.15 + 180 K = 453.15 K

So, P₁/T₁ = P₂/T₂

P₂ = P₁T₂/T₁

Substituting the values of the variables into the equation, we have

P₂ = P₁T₂/T₁

P₂ = 1 atm × 453.15 K/273.15 K

P₂ = 1 atm × 1.66

P₂ = 1.66 atm

We now need to find the total number of moles of each gas present

number of moles of nitrogen = mass of nitrogen, m/molar mass of nitrogen molecule M

n = m/M

m = 2.5 g and M = 2 × atomic mass of nitrogen (since it is diatomic) = 2 × 14 g/mol = 28 g/mol

So, n = 2.5 g/28 g/mol

n = 0.089 mol

number of moles of chlorine, n' = mass of chlorine, m'/molar mass of chlorine molecule M'

n' = m'/M'

m' = 13.3 g and M = 2 × atomic mass of chlorine (since it is diatomic) = 2 × 35.5 g/mol = 71 g/mol

So, n' = 13.3 g/71 g/mol

n' = 0.187 mol

So, the total number of moles of gas present is n" = n + n' = 0.089 mol + 0.187 mol = 0.276 mol

So, the partial pressure due to nitrogen gas, P = mole fraction of nitrogen × pressure of gas at 180 °C

P = n/n" × P₂

P = 0.089 mol/0.276 mol × 1.66 atm

P = 0.322 × 1.66 atm

P = 0.535 atm

8 0
3 years ago
an element in group two has two valence electrons. When forming a chemical bond it will most likely (gain, lose, share, or not r
Charra [1.4K]

Lose electrons - electrons want to fill their outer valence shell, so sometimes instead of gaining it is easier to lose some and have a filled outer shell

3 0
3 years ago
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