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Vikentia [17]
4 years ago
9

How many moles of magnesium is 1.25 x 1023 atoms of magnesium?

Chemistry
1 answer:
andrew-mc [135]4 years ago
4 0
The moles of magnesium in 1.25 x 1023 are 20.8 mol.
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alisha [4.7K]
Is identical to the nucleus of a normal atomic mass four helium atom i.e. a doubly ionised helium atom
5 0
3 years ago
) In the Deacon process for the manufacture of chlorine, HCl and O2 react to form Cl2 and H2O. Sufficient air (21 mole% O2, 79%
LiRa [457]

Answer:

Here's what I get.

Explanation:

1. Write the chemical equation

\rm 4HCl + O$_{2} \longrightarrow \,$ 2Cl$_{2}$ + 2H$_{2}$O

Assume that we start with 4 L of HCl

2. Calculate the theoretical volume of oxygen

\text{V}_{\text{O}_{2}}= \text{4 L HCl} \times \dfrac{\text{1 L O}_{2}}{\text{4 L HCl}} = \text{1 L O}_{2}}

3. Add 35% excess

\text{V}_{\text{O}_{2}}= \text{1 L O}_{2}} \times 1.35 = \text{1.35 L O}_{2}}

4. Calculate the theoretical volume of nitrogen

\text{V}_{\text{N}_{2}} = \text{1.35 L O}_{2}} \times \dfrac{\text{79 L N}_{2}}{\text{21 L O}_{2}}} = \text{5.08 L N}_{2}}

4. Calculate volumes of reactant used up

Only 85 % of the HCl is converted.

We can summarize the volumes in an ICE table

           4HCl     +       O₂    +    N₂   →    2Cl₂   +   2H₂O

I/L:          4               1.35         5.08         0              0

C/L:  -0.85(4)        -0.85(1)        0      +0.85(2)   +0.85(2)

E/L:     0.60             0.50        5.08       1.70          1.70

5. Calculate the mole fractions of each gas in the product stream

Total volume = (0.60 + 0.50 + 5.08 + 1.70 + 1.70) L = 9.58 L

\chi = \dfrac{\text{V}_{\text{component}}}{\text{V}_\text{total}} = \dfrac{\text{ V}_{\text{component}}}{\text{9.58}} = \text{0.1044V}_{\text{component}}\\\\\chi_{\text{HCl}} = 0.1044\times 0.60 = 0.063\\\\\chi_{\text{O}_{2}} = 0.1044\times 0.50 = 0.052\\\\\chi_{\text{N}_{2}} = 0.1044\times 5.08 = 0.530\\\\\chi_{\text{Cl}_{2}} = 0.1044\times 1.70 = 0.177\\\\\chi_{\text{H$_{2}${O}}} = 0.1044\times 1.70 = 0.177\\\\

8 0
3 years ago
How many moles of sulfur atoms are in 9.9 moles of Ag2S
GarryVolchara [31]

Answer:

9.9 moles of Ag₂S contain 9.9 moles of sulfur.

Explanation:

Given data:

Number of moles of Ag₂S = 9.9 mol

Number of moles of Sulfur = ?

Solution:

One mole of Ag₂S having 1 mole of sulfur.

In 9.9 moles:

9.9 moles × 1 = 9.9 moles

So 9.9 moles of Ag₂S contain 9.9 moles of sulfur.

6 0
3 years ago
stu dent has a large sample of a unknown solid material that is to big to fit into a graduated cylinder. he knows that it will n
Yakvenalex [24]

The density of the solid is  6.724 g/ml.

Density is the number of factors which can be people, animals, vegetation, or objects in a sure place. To calculate density, you divide the number of objects by the dimension of the place. The populace density of a rustic is the wide variety of human beings in that us of a divided by means of the location in square kilometers or miles.

The density of an amount to being counted is its mass divided by means of its quantity. it also includes measured at zero °C and at 1 atmosphere of stress. Density is vital in figuring out the buoyancy of materials in fluids, as well as in evaluating materials and other measurements.

The density of an object is certainly one of its maximum crucial and easily-measured physical properties. Densities are extensively used to perceive natural substances and to represent and estimate the composition of many varieties of combos.

density = mass/ volume

      = 975g/145ml

      = 6.724 g/ml

Learn more about density here:-brainly.com/question/1354972

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7 0
2 years ago
The area of a rectangle is 50 m2<br> If the height is 4 m, what is the<br> base?
Oliga [24]

Area = height × base

50 = 4 × base

Thus

base = 50/4

Base = 12.5 m

6 0
3 years ago
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