Answer:
In the case of s and p orbitals, there can be three types of overlap. s – s orbital overlap (formation of H2 molecule): The mutual overlap between the half-filled s orbitals of two atoms is called s – s overlap and the covalent bond formed is known as sigma (s) bond. e.g. formation of a hydrogen molecule from two hydrogen atoms.
Explanation:
Answer:
1. Decrease the pH
2. The pH remains unchanged
3. Decrease the pH
Explanation:
We can calculate the pH of a weak acid using the following expression:
![pH=-log [H^{+} ]=-log\sqrt{Ka \times Ca }](https://tex.z-dn.net/?f=pH%3D-log%20%5BH%5E%7B%2B%7D%20%5D%3D-log%5Csqrt%7BKa%20%5Ctimes%20Ca%20%7D)
[1]
where,
Ka is the acid dissociation constant
Ca is the initial concentration of the acid
<em>State whether each of the following would increase, decrease, or leave the initial pH unchanged and explain your reasoning</em>
- <em>Using the same weak acid, but having a higher concentration. </em>According to eq. [1], a higher Ca leads to a higher [H⁺] and a lower pH.
- <em>Using 80.00 mL of this weak acid instead of 40.00 mL.</em> pH refers to a concentration, which is an intensive property, so it does not change when we change the amount of matter.
- <em>Using a different weak acid that has a larger Ka value.</em> According to eq. [1], a higher Ka leads to a higher [H⁺] and a lower pH.
Answer:
The third line
Explanation:
The first one us wrong because they're not all found inside,electron is outside.
The second one is wrong as I explained previously.
Lastly the fourth line is wrong because protons are found in the nucleus.
Answer:
92.6 g.
Explanation:
- The balanced equation is:
CaC₂ + N₂ → CaCN₂ + C.
- It is clear that 1.0 mole of CaC₂ reacts with 1.0 mole of N₂ to produce 1.0 mole of CaCN₂ and 1.0 mole of C.
- We need to calculate the no. of moles of 265.0 g of CaCN₂ produced using the relation:
n = mass / molar mass = (265.0 g) / (80.102 g/mol) = 3.308 mol.
- We should get the no. of moles of N₂ needed to produce 3.308 mol of CaCN₂.
∵ 1.0 mole of N₂ produces → 1.0 mole of CaCN₂.
<em>∴ 3.308 mole of N₂ produces → 3.308 mole of CaCN₂.</em>
- Now, we can get the grams of N₂ consumed to produce 265.0 g of CaCN₂:
∴ The grams of N₂ = n x molar mass = (3.308 mole)(28.0 g/mol) = 92.63 g = 92.6 g.
Answer:
CaO, CaF2, or CaCl2
Explanation:
In an ionic compound, the charges need to balance out. This is the only set of compounds that fits this criteria.
