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2 years ago

How do you look for elements with similar properties on the periodic table?

Chemistry

1 answer:

Lena [83]2 years ago

5 0

Elements in a group or a column have the same number of outer electrons so they have similar chemical properties

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Wat helps measure 26 ML of a liquid

kotegsom [21]

Answer:

6 liquids

Explanation:

because yea

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3 years ago

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Which of the following is a precipitation reaction?

fredd [130]

Answer:

B is a precipitation reaction.

Explanation:

This is because a precipitation reaction is when a solid is made from the combination of cations and anions in a solution to create a solid.

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2 years ago

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How many atoms are in a 1.8 mol sample of Magnesium (Mg)?

Gnom [1K]

Answer:

1.1 × 10²⁴ atoms Mg

General Formulas and Concepts:

Atomic Structure

Moles
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

Using Dimensional Analysis

Explanation:

Step 1: Define

Identify

[Given] 1.8 mol Mg

[Solve] atoms Mg

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

[DA] Set up: $\displaystyle 1.8 \ mol \ Mg(\frac{6.022 \cdot 10^{23} \ atoms \ Mg}{1 \ mol \ Mg})$
[DA] Multiply [Cancel out units]: $\displaystyle 1.08396 \cdot 10^{24} \ atoms \ Mg$

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

1.08396 × 10²⁴ atoms Mg ≈ 1.1 × 10²⁴ atoms Mg

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2 years ago

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Which is an example of a set point for the body? A. hair color B. type of blood C. thumb crossing style D. amount of blood gluco

Mama L [17]

The Answer Is B Type Of Blood

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2 years ago

Consider the reaction below. Initially the concentration of SO2Cl2 is 0.1000 M. Solve for the equilibrium concentration of SO2Cl

tensa zangetsu [6.8K]

Answer:

$[SO_2Cl_2] = 0.09983 M$

Explanation:

Write the balance chemical equation ,

$SO_2Cl_2((g) = SO_2(g) + Cl_2(g)$

initial concenration of $SO_2Cl_2((g) =0.1M$

lets assume that degree of dissociation= $\alpha$

concenration of each component at equilibrium:

$[SO_2Cl_2] = 0.1-0.1\alpha$

$[SO_2] = 0.1\alpha$

$[Cl_2] = 0.1\alpha$

$Kc =\frac{0.1\alpha \times 0.1\alpha}{0.1-0.1\alpha}$

$Kc =\frac{0.1\alpha \times \alpha}{1-\alpha}$

as $\alpha$ is very small then we can neglect $1-\alpha$

therefore ,

$Kc ={0.1\alpha \times \alpha}$

$\alpha =\sqrt{\frac{Kc}{0.1}}$

$\alpha = 1.73 \times 10^{-3}$

Eqilibrium concenration of $[SO_2Cl_2] = 0.1-0.1\alpha = 0.1-0.1\times 0.00173$

$[SO_2Cl_2] = 0.09983 M$

4 0

2 years ago