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VikaD [51]
2 years ago
9

A student places a large pot of cold water on a stove and heats it for one minute. Then she takes the pot of water off the burne

r and places it on the counter. Which best describes the convection currents?
A.Convection currents move thermal energy from the stove to the pot, and then from the pot to the water.
B.After the stove is turned off, convection currents continue to transfer energy through the water for a period of time.
C.Convection currents in the water cause warmer, denser water to rise and transfer energy upward.
D.When the stove is turned on, convection currents cause an increase in the chemical energy of water molecules.
Physics
1 answer:
guajiro [1.7K]2 years ago
8 0
After the stove is turned off, convection currents continue to transfer energy through the water for a period of time
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What is necessary to designate a position? A. a reference point B. a direction C. fundamental units D. motion E. all of these
max2010maxim [7]

Answer:

E. all of these

Explanation:

The designation of a point in space all the points that necessary

- reference point

- a direction

- fundamental units

- a direction

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all are necessary to designate a point in space. Hence option E is correct.

For example in simple harmonic motion we need to specify all the above factors of the object in order to designate the position of the object.  

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Quarks are thought to be the basic component of what?
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a surface recieving sound is moved from it original position to a position three times farther away from the source of the sound
Delicious77 [7]
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7 0
3 years ago
The distance between two particles is 2 centimeters. If the distance is increased to 4 centimeters, the force will be ?
postnew [5]

Answer:

The new force is 1/4 of the previous force.

Explanation:

Given

Initial\ Distance = 2cm ---- r_1

New\ Distance = 4cm --- r_2

Required

Determine the new force

Let the two particles be q1 and q2.

The initial force F1 is:

F_1 = \frac{kq_1q_2}{r_1^2} --- Coulomb's law

Substitute 2 for r1

F_1 = \frac{kq_1q_2}{2^2}

F_1 = \frac{kq_1q_2}{4}

The new force (F2) is

F_2 = \frac{kq_1q_2}{r_2^2}

Substitute 4 for r2

F_2 = \frac{kq_1q_2}{4^2}

F_2 = \frac{kq_1q_2}{4*4}

F_2 = \frac{1}{4}*\frac{kq_1q_2}{4}

Substitute F_1 = \frac{kq_1q_2}{4}

F_2 = \frac{1}{4}*F_1

F_2 = \frac{F_1}{4}

The new force is 1/4 of the previous force.

3 0
2 years ago
A car with a constant velocity of 22 m/s is driven for 6.8 s. How far did it travel? (v =∆ d/∆t)
Genrish500 [490]

Answer:

C. 150 m

Explanation:

22 m/s x 6.8 = 149.6

3 0
3 years ago
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