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RSB [31]
4 years ago
9

Angela has been feeling fatigued. A test to check the basal metabolic rate revealed that she has a low metabolic rate. What is A

ngela's possible diagnosis?
Physics
1 answer:
polet [3.4K]4 years ago
8 0
Here is the answer to the given question above. If Angela has been feeling fatigued and a test is used to check the basal metabolic rate and revealed that she has a low metabolic rate, therefore, the possible diagnosis for Angela would be HYPOTHYROIDISM. <span>The BMR test works by precisely measuring the amount of oxygen that you consume when your body is basal, or completely at rest. Hope this answers your question.</span>
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Identify Label these cell parts
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Answer:

I don't know this answer because I am not American

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What's the momentum (in kg-m/s) of a cannonball with a mass of 21 moving with a velocity of 25 m/s?
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P=mv
P=21*25=525 kg*m/s
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3 years ago
A golf ball is rolling in the grass. What must happen to stop the ball from continuing to roll?
slamgirl [31]
The net force must be zero

This is in accordance to Newton's first law, which states that any object in motion will remain in motion and any object at rest will remain at rest unless acted upon by an unbalanced force. An unbalanced force is one where the net force is not zero. If no unbalanced force is applied to a moving object, it will keep moving forever. The reason that we do not observe this in our daily lives is due to friction acting as the unbalanced force.
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3 years ago
You are on an airplane traveling 30° south of due west at 180 m/s with respect to the air. The air is moving with a speed 31 m/s
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6 0
3 years ago
#1 Not sure where to start. This is for AP Physics!
yaroslaw [1]

First,

\rho=\dfrac mV

where \rho is density, m is mass, and V is volume. We can compute the volume of the roll:

2.7\,\dfrac{\mathrm g}{\mathrm{cm}^3}=\dfrac{1275\,\mathrm g}V

\implies V\approx472.22\,\mathrm{cm}^3\approx4.72\,\mathrm m^3

When the roll is unfurled, the aluminum will be a rectangular box (a very thin one), so its volume will be the product of the given area and its thickness x. Note that we're assuming the given area is not the actual total surface area of the aluminum box, but just the area of the largest face (i.e. the area of one side of the unrolled sheet of aluminum).

So we have

V=Ax

where A is the given area, so

4.72\,\mathrm m^3=\left(18.5\,\mathrm m^2\right)x

\implies x\approx0.255\,\mathrm m=255\,\mathrm{mm}

If we're taking significant digits into account, the volume we found would have been V=470\,\mathrm m^3, in turn making the thickness x=250\,\mathrm{mm}.

8 0
3 years ago
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