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tigry1 [53]
3 years ago
7

If 65,000 J of energy were transferred to 450 g of water at 20˚C. What would have been the final temperature of the water?

Chemistry
2 answers:
serg [7]3 years ago
5 0

Answer:

500g

Explanation:

katrin [286]3 years ago
5 0

Answer:Suppose that during the Icy Hot lab that 65 KJ of energy were transfered to 450 g of water at 20 degrees C. What would have been the final temerpatur

Explanation:

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The equilibrium constant, Kp, for the following reaction is 0.497 at 500K.PCl5(g) PCl3(g) + Cl2(g)If an equilibrium mixture of t
Anestetic [448]

<u>Answer:</u> The equilibrium partial pressure of chlorine gas is 0.360 atm

<u>Explanation:</u>

For the given chemical equation:

PCl_5(g)\rightleftharpoons PCl_3(g)+Cl2(g)

The expression of K_p for above reaction follows:

K_p=\frac{p_{Cl_2}\times p_{PCl_3}}{p_{PCl_5}}

We are given:

K_p=0.497\\p_{PCl_3}=0.651atm\\p_{PCl_5}=0.471atm

Putting values in above equation, we get:

0.497=\frac{p_{Cl_2}\times 0.651}{0.471}\\\\p_{Cl_2}=0.360atm

Hence, the equilibrium partial pressure of chlorine gas is 0.360 atm

5 0
3 years ago
I'm very confused can someone help me please I would really appreciate it
sasho [114]
1. temperature is dependent
2. energy is independent
3. the graph looks like a line sloping upward
4. the line means that as energy increases the temperature also increases
5. a straight line would mean that as energy increases temperature remains constant
sorry that's all I can do
7 0
3 years ago
How many milliliters of 0.0510 m edta are required to react with 50.0 ml of 0.0200 m cu2 ?
krok68 [10]
Cu  ions plus EDTA2-   ->cu(EDTA)2-  plus 2H-
   number  of  moles  of  CU  ions  used  which is   equal to  molarity  multiplied  by    volume  in  litres
that  is  50xo.o2  divided  by 1000  that  is  0.001moles
Since  ratio  is  1:1  the  moles  of EDTA  is  also0.001moles
volume  of  EDTA  is  0.001  divided  by  0.0510m  which  is  0.0196  litres in  ml is  0.0196x1000  which  is  19.61ml
4 0
3 years ago
Using the following thermochemical equation, determine the amount of heat produced per kg of CO2 formed during the combustion of
Arisa [49]

Answer:  12033 kJ of heat produced per kg of CO_2 formed during the combustion of benzene

Explanation:

The balanced chemical equation for combustion of benzene is :

2C_6H_6(l)+15O_2(g)\rightarrow 12CO_2(g)+6H_2O(g)  \Delta H°rxn = -6278 kJ

Exothermic reactions are defined as the reactions in which energy of the product is lesser than the energy of the reactants. The total energy is released in the form of heat and \Delta H for the reaction comes out to be negative.

\text{Moles of }CO_2=\frac{\text{given mass}}{\text{Molar Mass}}=\frac{1000g}{44g/mol}=23mol      (1kg=1000g)

According to stoichiometry :

12 moles of CO_2 on combustion produce heat = 6278 kJ

Thus 23 mole of CO_2 on combustion produce heat =\frac{6278}{12}\times 23=12033kJ

Thus 12033 kJ of heat produced per kg of CO_2 formed during the combustion of benzene

5 0
3 years ago
What is a large area of air with the same temperature?.
Yuliya22 [10]

Sorry this is late but it would be the air mass

Hope this halpes :))

6 0
2 years ago
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