1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dahasolnce [82]
4 years ago
8

Check all statements below that are true.

Chemistry
1 answer:
docker41 [41]4 years ago
3 0

Answer:

The answers are A,B,C.

Explanation: Just got it right on Edge 2020

You might be interested in
A student is preparing to perform a series of calorimetry experiments. She first wishes to determine the calorimeter constant (C
laila [671]

Answer:

  • First choice: 99 J/K

Explanation:

<u>1) First law of thermodynamic (energy balance)</u>

  • Heat released by the the hot water (345K ) = Heat absorbedby the cold water (298 K) + Heat absorbed by the calorimeter

<u>2) Energy change of each substance:</u>

  • General formula:

     

Heat released or absorbed = mass × Specific heat × change in temperature

  • density of water: you may take 0.997 g/ ml as an average density for the water.

  • mass of water: mass = density × volume = 50.0 ml × 0.997 g/ml = 49.9 g

  • Specif heat of water: 1 cal / g°C

  • Heat released by the hot water:

       Heat₁ = 49.9 g × 1 cal / g°C × (345 K - 317 K) = 49.9 g × 1 cal / g°C × (28K)

  • Heat absorbed by the cold water:

       Heat₂ = 49.9 g × 1 cal / g°C × (317 K - 298 K) = 49.9 g × 1 cal / g°C × (19K)

  • Heat absorbed by the calorimeter

       Heat₃ = Ccal × (317 K - 298 K) = Ccal × (19K)

<u>4) Balance</u>

  • Heat₁ = Heat₂ + Heat₃

49.9 g × 1 cal / g°C × (28 K) = 49.9 g × 1 cal / g°C × (19 K) + Ccal × (19 K)

  • Solve for Ccal

Ccal = [49.9 g × 1 cal / g°C × (28 K) - 49.9 g × 1 cal / g°C × (19 K) ] / 19K

Ccal = 23.6 cal/ K

  • Convert to cal / K to Joule / K

  • 1 cal = 4.18 Joule

       23.6 cal / K × 4.18 J / cal = 98.6 J/K

Which rounded to 2 signficant figures leads to 99 J/k, which is the first choice.

4 0
4 years ago
Integrated Problem 01.69 With current spectroscopic techniques, chemists are generally able to determine the structure of an unk
Gnesinka [82]

a or c becuse it means you should answer it very wiseley

5 0
3 years ago
The sum of the atomic mass values of the atoms in a chemical formula is known as ____________.​
nydimaria [60]

Answer:

I believe this is called the 'molar mass'

5 0
3 years ago
Where is a divergent boundary most likely to be found?
nexus9112 [7]

Answer:

a

Explanation

Bc I took the test, good luck with that guys

7 0
2 years ago
Which statement describes clean air as a natural resource? Select three options.
Mumz [18]

Answer:

a,d,e

Explanation:

its a,d, and e because clean air keeps us alive and other organisms need it to stay alive

6 0
3 years ago
Read 2 more answers
Other questions:
  • 17)<br> How many grams are in 0.02 moles of beryllium iodide, Bel2?
    15·2 answers
  • What was Ernest Rutherford's atom model name
    15·2 answers
  • A 0.590 gram sample of a metal, M, reacts completely with sulfuric acid according to:M(s) +H2SO4(aq) --&gt; MSO4(aq) +H2(g)A vol
    12·1 answer
  • Match each number to how it would appear in scientific notation.
    7·2 answers
  • Cual es el propósito de la línea escalonada gruesa de la tabla periódica
    11·1 answer
  • Which of the following is the best explanation of why an ionic compound formula is a ratio of atoms
    14·1 answer
  • Which substance in the table below will heat up the fastest? water helium diamond or glass
    6·1 answer
  • To find time, t, the age of the universe, you must first isolate the variable t. Rewrite the velocity equation v = d / t so that
    11·1 answer
  • Animation shows a complete revolution of the Earth around the sun. What happens during this time? The moon makes one complete ph
    13·1 answer
  • What volumes of 0.200 M HCOOH and 2.00 M NaOH would make 500. mL of a buffer with the same pH as one made from 475 mL of 0.200 M
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!