Answer:
A. t = 0.30s
B. s = 0.204m
C. Vfinal = 4.96 m/s
Explanation:
Using equations of motion,
Initial velocity, Vo = 2 m/s
Distance from the rable to the floor, S = 1.05 m
Acceleration due to gravity, a = 9.81m/s2
Using S = Vot + 1/2at^2
Inputting values,
1.05 = 2t + 1/2*(9.81)*t^2
4.9t^2 + 2t - 1.05 = 0
Solving the quadratic equation,
t = 0.30s
B. At the tabletop, Vo = Vfinal = 2m/s
Vo = 0m/s
Using the equation of motion,
Vfinal^2 = Vo^2 + 2as
Where s = horizontal distance
(2)^2 = 0^2 +2 * 9.81 * s
s = 4/19.62
= 0.204 m
C. For the vertical component, the initial velocity of the ball ia right at the maximum height before it increases vertically. Vfinal is the velocity when the object hust hit the ground.
Back to Vo = 2m/s
Vfinal = ?
S = 1.05 m
Using the equation of motion,
Vfinal^2 = Vo^2 + 2as
= 2^2 + 2*9.81*1.05
= 4 + 20.601
Vfinal = sqrt(24.601)
= 4.96m/s