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3 years ago

Please help to solve thisFind H.C.F m^3 - 1, m^4 + m^2 + 1, m^2+ m + 1

Mathematics

1 answer:

Nikitich [7]3 years ago

7 0

Answer:

m^2+m+1

Step-by-step explanation:

m^3 - 1= (m-1)(m^2+m+1)
m^4 + m^2 + 1= m^4+2m^2+1 - m^2= (m^2+1)^2 -m^2= (m^2+m+1)(m^2-m+1)
m^2+ m + 1

HCF= m^2+m+1 which is the factor of all three polynomials

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if a town with a population of 500 doubles in size ever 9 years, what will the population be 36 years from now?

s344n2d4d5 [400]

The population of the town in 36 years would be 8000.

<h3>What would be the population of the town in 36 years?</h3>

The formula that can be used to determine the town's population is:
FV = P (1 + r)^n

Where:

FV = Future value
P = Present value
R = rate of growth = 100%
N = number of years = 36/9 = 4

500 x 2^4 = 8000

To learn more about future value, please check: brainly.com/question/18760477

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2 years ago

Make x the subject of y=alog(5x)

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Answer:

x = 0.2(10^y/a).

Step-by-step explanation:

y = alog(5x)

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3 years ago

What is the factorization of x^2-6x+5

zimovet [89]

The answer is (x-5) (x-1)

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3 years ago

How would you solve this? help.

Eddi Din [679]

Answer:

<em>Center: (3,3)</em>

<em>Radius: </em> $2\sqrt{5}$ <em />

Step-by-step explanation:

<u>Midpoint and Distance Between two Points</u>

Given two points A(x1,y1) and B(x2,y2), the midpoint M(xm,ym) between A and B has the following coordinates:

$\displaystyle x_m=\frac{x_1+x_2}{2}$

$\displaystyle y_m=\frac{y_1+y_2}{2}$

The distance between both points is given by:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Point (5,7) is the center of circle A, and point (1,-1) is the center of the circle B. Given both points belong to circle C, the center of C must be the midpoint from A to B:

$\displaystyle x_m=\frac{5+1}{2}=\frac{6}{2}=3$

$\displaystyle y_m=\frac{7-1}{2}=\frac{6}{2}=3$

Center of circle C: (3,3)

The radius of C is half the distance between A and B:

$d=\sqrt{(1-5)^2+(-1-7)^2}$

$d=\sqrt{16+64}=\sqrt{80}=\sqrt{16*5}=4\sqrt{5}$

The radius of C is d/2:

$r =4\sqrt{5}/2 = 2\sqrt{5}$

Center: (3,3)

Radius: $2\sqrt{5}$

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3 years ago

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The correct answer is 1,950

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3 years ago

Please help to solve thisFind H.C.F m^3 - 1, m^4 + m^2 + 1, m^2+ m + 1​

Please help to solve thisFind H.C.F m^3 - 1, m^4 + m^2 + 1, m^2+ m + 1