Answer:
The pressure drop across the pipe also reduces by half of its initial value if the viscosity of the fluid reduces by half of its original value.
Explanation:
For a fully developed laminar flow in a circular pipe, the flowrate (volumetric) is given by the Hagen-Poiseulle's equation.
Q = π(ΔPR⁴/8μL)
where Q = volumetric flowrate
ΔP = Pressure drop across the pipe
μ = fluid viscosity
L = pipe length
If all the other parameters are kept constant, the pressure drop across the circular pipe is directly proportional to the viscosity of the fluid flowing in the pipe
ΔP = μ(8QL/πR⁴)
ΔP = Kμ
K = (8QL/πR⁴) = constant (for this question)
ΔP = Kμ
K = (ΔP/μ)
So, if the viscosity is halved, the new viscosity (μ₁) will be half of the original viscosity (μ).
μ₁ = (μ/2)
The new pressure drop (ΔP₁) is then
ΔP₁ = Kμ₁ = K(μ/2)
Recall,
K = (ΔP/μ)
ΔP₁ = K(μ/2) = (ΔP/μ) × (μ/2) = (ΔP/2)
Hence, the pressure drop across the pipe also reduces by half of its initial value if the viscosity of the fluid reduces by half of its value.
Hope this Helps!!!
In order to fly, you must have a device/mechanism that will release hot air, causing it to fly. A jet pack will do the job.
Answer:
What is one of the “don’ts” in drawing dimension lines? they should never be labeled they should never be stacked they should never cross each other they should never have only one measurement value
Answer:
t = 59.37 s
Explanation:
Given data:
thermal diffusivity 
theraml conductivity = k = 22 W/m.K
h = 300 W/ m^2.K
= 25 degree C = 298 k
= 60 degree C = 333 k
= 75 degree C = 348 L
diameter d = 0.1 m
characteristics length Lc = r/3 = = 0.0166




at Bi = 0.226
Ai = 0.982




-1.187 = - 0.02t
t = 59.37 s
Answer:
Explanation:
Given
wavelength 
distance between two slits 
Screen is placed at a distance 
Location of a (n+1)th bright fringe is given by

for nth bright fringe

Distance between two bright fringes

