Answer:
B. To accurately measure spark advance, use a timing light that incorporates an
ignition advance meter. The spark advance cannot be determined by listening to the way the engine sounds.
Answer:
The required pumping head is 1344.55 m and the pumping power is 236.96 kW
Explanation:
The energy equation is equal to:

For the pipe 1, the flow velocity is:

Q = 18 L/s = 0.018 m³/s
D = 6 cm = 0.06 m

The Reynold´s number is:


Using the graph of Moody, I will select the f value at 0.0043 and 335339.4, as 0.02941
The head of pipe 1 is:

For the pipe 2, the flow velocity is:

The Reynold´s number is:


The head of pipe 1 is:

The total head is:
hi = 1326.18 + 21.3 = 1347.48 m
The required pump head is:

The required pumping power is:

Answer:
Hook's law holds good up to. A elastic limit. B. plastic limit. C.yield point. D.Breaking point
Answer:
Circuit attached with explanation
Explanation:
Hi Dear,
A circuit is attached for your reference.
When you press "start" PB, the supply reaches the motor starter relay coil "M" that is also in parallel with the "start" PB which allows the motor to remain ON even when you release "start" PB as supply to relay coil is directly from supply "L" through "M".
To stop motor just press "stop" PB and the circuit breaks which de-energize the relay coil and the motor stops.
Hope this finds easy to you.