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Viefleur [7K]
3 years ago
5

If 100 J of heat is added to a system so that the final temperature of the system is 400 K, what is the change in entropy of the

system? a)- 0.25 J/K b)- 2.5 J/K c)- 1 J/K d)- 4 J/K
Engineering
1 answer:
Vitek1552 [10]3 years ago
4 0

Answer:

0.25 J/K

Explanation:

Given data in given question

heat (Q) = 100 J

temperature (T) = 400 K

to find out

the change in entropy of the given system

Solution

we use the entropy change equation here i.e  

ΔS = ΔQ / T           ...................a

Now we put the value of heat (Q) and Temperature (T) in equation a

ΔS is the entropy change, Q is heat and T is the temperature,  

so that

ΔS = 100/400 J/K

ΔS = 0.25 J/K

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Answer:

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Explanation:

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GIven

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We get F₁  and F₂ as follows:

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Nef*Cos 12º -  F₂*Sin 12º = W

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We can see the pic shown in order to understand the question.

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Step by step working is shown in the images attached herewith.

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