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Anni [7]
3 years ago
9

A car increases its velocity from zero to 97 km/h in 8.4 s. What is its acceleration?

Physics
1 answer:
ser-zykov [4K]3 years ago
3 0

Answer:

a=\frac{v-u}{t}

v=final velocity =97km/h(change to m/s) =26.9m/s NEVER FORGET TO DO THAT BECAUSE TIME IS GIVEN IN SECONDS

u=initial velocity  0 m/s

t=time 8.4s

a=\frac{26.9-0}{8.4}

a= 3.2m/2^{2}

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Janetta ran a campaign for student body president, and she really wanted to win. She gave election buttons to everyone and told
SVEN [57.7K]

Answer:

No, because she is hoping that people will vote for her.

Explanation:

Altruism is when you do something for others and have very little expectation of getting something in return. In this case, Janetta expected something in return from her friends. We may not also be sure of the sincerity of Janetta appreciating friendship. From the above definition of altruism, we conclude that Janetta's actions are not altruistic because she hoped that people will vote for her.

3 0
3 years ago
What property do all three of these common household substances have in common?
Oxana [17]

Answer:

whats the items

Explanation:

4 0
3 years ago
Which of the following statements is true?
Alborosie
My guess is A. I'm not 100% positive but i'm pretty sure.
8 0
3 years ago
A spring has a force constant k, and an object of mass m is suspended from it. The spring is cut in half and the same object is
kenny6666 [7]

Answer:

f2/f1 = \sqrt{2}

Explanation:

From frequency of oscillation

f = 1/2pi *\sqrt{k/m}

Initially with the suspended string, the above equation is correct for the relation, hence

f1 = 1/2pi *\sqrt{k/m}

where k is force constant and m is the mass

When the spring is cut into half, by physics, the force constant will be doubled as they are inversely proportional

f2 = 1/2pi *\sqrt{2k/m}

Employing f2/ f1, we have

f2/f1 = \sqrt{2}

3 0
3 years ago
3 نقطة (نقاط)
Molodets [167]

The work-energy theorem says that the total work done on the block is equal to the difference of its kinetic energies at points B and A. Then the total work done on the block is

W_{\rm total} = K_B - K_A = 4.0\,\mathrm J - 5.0\,\mathrm J = -1.0\,\mathrm J

Friction acts on the block to oppose its motion, so it does negative work on the block, -4.5 J.

The only other force acting on the block as it moves is the force <em>P</em>. Let W_P be the work done by the force <em>P</em>. Then the total work done on the block is

W_{\rm total} = W_P + W_{\rm friction} \iff -1.0\,\mathrm J = W_P - 4.5 \,\mathrm J \implies W_P = \boxed{3.5\,\mathrm J}

5 0
2 years ago
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