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zlopas [31]
3 years ago
11

What is the difference between Volt and Amber

Physics
1 answer:
sergejj [24]3 years ago
4 0
Now, it's pretty simple. And if you meant "amber" as in "amp" and "volt" and in "voltage" maybe. Then this is simple.

An ampere (or amp) is a measure of the amount of electricity, called "current," in a circuit, while voltage (or volt) is a measure of the force behind that electricity's motion.<span> </span>

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A well-trained athlete can run 400m in 47s, what is the athlete’s velocity?
AnnZ [28]

Answer:

8.51 m/s

Explanation:

Velocity = Displacement/Time

Velocity = 400 m ÷ 47 s

<u>Velocity</u><u> </u><u>=</u><u> </u><u>8</u><u>.</u><u>5</u><u>1</u><u> </u><u>m</u><u>/</u><u>s</u>

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2 years ago
Which statement is accurate about seasonal temperatures in North carolina
Alex
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3 years ago
Two physics students are arguing about superconductors and their discovery, Jeffe says that he can use a
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2 years ago
0.0010 kg pellet is fired at a speed of 52.2 m/s at a motionless 3.3 kg piece of balsa wood. When the pellet
Paraphin [41]

The formula for momentum is p = m*v

The conservation of momentum suggests:

m*vi = m*vf (initial mass times initial velocity = final mass times final velocity or initial momentum = final momentum)

(0.0010)(52.2) = (0.0010 + 3.3)vf

vf = (0.0010)(52.2)/(0.0010 + 3.3) = 0.0522/3.301 ≈ 0.01581 m/s

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7 0
3 years ago
A circular window of 30 cm diameter in a submarine can withstand a maximum force of 5.20 × 105 N. The maximum depth in a lake to
Svetach [21]

Answer: Option (b) is the correct answer.

Explanation:

The given data is as follows.

         F = 5.20 \times 10^{5} N

         g = 9.8 m/s

         radius = \frac{diameter}{2}

                    = \frac{30 cm}{2} = 15 cm = 0.15 m   (as 1 m = 100 cm)

Formula to calculate depth is as follows.

        F = \rho \times g \times h \times A

or,      h = \frac{F}{\rho \times g \times A}        

       h = \frac{5.2 \times 10^{5}}{1000 \times 9.8 \times (3.1416 \times (0.15 m^{2})}

           = 751 m

Thus, we can conclude that the maximum depth in a lake to which the submarine can go without damaging the window is closest 750 m.

3 0
3 years ago
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