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lakkis [162]
3 years ago
13

Testing Plant Growth with Fertilizer

Physics
1 answer:
kykrilka [37]3 years ago
5 0

b) by the end of the fifth day, group b will be more than one cm taller than group a. eliminate

Explanation:

The correct prediction based on the data shown is that by the end of the fifth day, group B plants will be more than 1cm taller than group A plants.

let us examine the table closely;

Day Group A (Water Only) Plant Height (cm) Group B (Water and Fertilizer)

1                                         2.0                                                 2.0

2                                         2.2                                                 2.3

3                                         2.3                                                 2.8

4                                        2.5                                                  3.2

5                                        2.6                                                  3.8

We can see that by the end of the fifth day, the height differences between the two plants, 3.8 - 2.6 = 1.2cm, this is greater than 1cm. This claim from the experiment is very correct.

Other predictions are false.

learn more:

Experiment brainly.com/question/5096428

#learnwithBrainly

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gayaneshka [121]

From the calculations, the value of the acceleration due to gravity is 0.38 m/s^2.

<h3>What is weight?</h3>

The weight of an object is obtained as the product of the mass of the body and the acceleration due to gravity.

Thus;

When;

mass = 120 kg

weight =  46 N

acceleration due to gravity = 46 N/120 kg

=0.38 m/s^2

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7 0
2 years ago
(a) Calculate the acceleration due to gravity on the surface of the Sun.
Ira Lisetskai [31]
<h2>a)Acceleration due to gravity on the surface of the Sun is 274.21 m/s²</h2><h2>b) Factor of increase in weight is 27.95</h2>

Explanation:

a) Acceleration due to gravity

                      g=\frac{GM}{r^2}

 Here we need to find acceleration due to gravity of Sun,

                G = 6.67259 x 10⁻¹¹ N m²/kg²

    Mass of sun, M = 1.989 × 10³⁰ kg

    Radius of sun, r = 6.957 x 10⁸ m

Substituting,

                g=\frac{6.67259\times 10^{-11}\times 1.989\times 10^{30}}{(6.957\times 10^8)^2}\\\\g=274.21m/s^2

Acceleration due to gravity on the surface of the Sun = 274.21 m/s²

b) Acceleration due to gravity in earth = 9.81 m/s²

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8 0
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4 0
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What is the amount of work done when a force of 10N moves a 20kg mass of 8 meters?
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Yo sup??

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3 0
3 years ago
When the acceleration of a mass on a spring is zero, the velocity is at a
Sergeu [11.5K]

1) Maximum

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Explanation:

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F=kx

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k is the spring constant

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Also we know from Newton's second law that we can write

F=ma

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m is the mass

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On the other hand, we know that the total mechanical energy of the system mass-spring is constant, and it is given by

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When the velocity of a mass on a spring is zero, the acceleration is at a  maximum

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