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lakkis [162]
3 years ago
13

Testing Plant Growth with Fertilizer

Physics
1 answer:
kykrilka [37]3 years ago
5 0

b) by the end of the fifth day, group b will be more than one cm taller than group a. eliminate

Explanation:

The correct prediction based on the data shown is that by the end of the fifth day, group B plants will be more than 1cm taller than group A plants.

let us examine the table closely;

Day Group A (Water Only) Plant Height (cm) Group B (Water and Fertilizer)

1                                         2.0                                                 2.0

2                                         2.2                                                 2.3

3                                         2.3                                                 2.8

4                                        2.5                                                  3.2

5                                        2.6                                                  3.8

We can see that by the end of the fifth day, the height differences between the two plants, 3.8 - 2.6 = 1.2cm, this is greater than 1cm. This claim from the experiment is very correct.

Other predictions are false.

learn more:

Experiment brainly.com/question/5096428

#learnwithBrainly

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Oxygen makes up more than 90 percent of the volume of the Earth's crust. Is oxygen found as a solid, liquid, or gas?
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a student throws three pencils into the trash can, only one lands in the can and the other hits the window each time? precise or
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3 years ago
Two identical particles, each with a mass of 4.5 mg and a charge of 30 nC, are moving directly toward each other with equal spee
e-lub [12.9K]

Answer:

   r₁ = 20.5 cm

Explanation:

In this exercise we can use the conservation of energy

the gravitational power energy is always attractive, the electrical power energy is repulsive if the charges are of the same sign

starting point.

        Em₀ = U_g + U_e + K = -G \frac{m_1m_2}{r} +k \frac{q_1q_2}{r} - 2 ( \frac{1}{2}  m v^2)

the two in the kinetic energy is because they are two particles

final point. When it is detained

        Em_f = U_g + U_e = -G \frac{m_1m_2}{r_1} + k \frac{q_1q_2}{r_1}

the energy is conserved

        Em₀ = em_f

the charges and masses of the two particles are equal

         -G \frac{m^2}{r} + k \frac{q^2}{r} + m v^2 = - G \frac{m^2}{r_1} + k \frac{q^2}{r_1}        

         

sustitute the values

-6.67-11 (4.5 10-3) ² / 0.25 - 9, 109 (30 10-9) ² / 0.25 + 4.5 10-3 4² = - 6.67 10- 11 (4.5 10-3) ² / r1 -9 109 (30 10-9) ² / r1

    -5.4 10⁻¹⁵ + 3.24 10⁻⁵ - 7.2 10⁻⁵ = -1.35 10⁻¹⁵ / r₁  + 8.1 10⁻⁶ / r₁

We can see that the terms that correspond to the gravitational potential energy are much smaller than the terms of the electric power, which is why we depress them.

      3.24 10⁻⁵ - 7.2 10⁻⁵ =  8.1 10⁻⁶ / r₁

      -3.96 10⁻⁵ = 8.1 10⁻⁶ / r₁

      r₁ = 8.1 10⁻⁶ /3.96 10⁻⁵

      r₁ = 2.045 10⁻¹ m

      r₁ = 20.5 cm

4 0
3 years ago
A student is doing an investigation into the masses of different materials of different densities.
Dmitrij [34]

Answer:

0.0118125 (kg)

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So mass of the cube = (3500)(3.375*10^-6) = 0.0118125 (kg)

5 0
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