Answer:
What mass (g) of barium iodide is contained in 188 mL of a barium iodide solution that has an iodide ion concentration of 0.532 M?
A) 19.6
B) 39.1
C) 19,600
D) 39,100
E) 276
The correct answer to the question is
B) 39.1 grams
Explanation:
To solve the question
The molarity ratio is given by
188 ml of 0.532 M solution of iodide.
Therefore we have number of moles = 0.188 × 0.532 M = 0.100016 Moles
To find the mass, we note that the Number of moles = 
from which we have
Mass = Number of moles × molar mass
Where the molar mass of Barium Iodide = 391.136 g/mol
= 0.100016 moles ×391.136 g/mol = 39.12 g
F = (mass)(acceleration) = ma
m = 55 kg
Vi = 20 m/s
t = 0.5 s
Vf = 0 m/s (since she was put to rest)
a=(Vf-Vi)/t
a=(0-20)/5
a = 40 m/s^2 (decelerating)
F = ma = (55 kg)(40 m/s^2)
F = 2200 N
We have to draw the structural formula of trans-1-bromo-3-isopropylcyclobutane.
The structure is shown below in Figure1.
The molecule trans-1-bromo-3-isopropylcyclobutane has four atoms in the skeleton and Br atom is attached at 1 position and isopropyl group at 3-position.
Trans structure means both groups are in opposite directions.
Answer:
Inhibition and tolerance.
Explanation:
Competitive inhibitors are characterized by being chemicals that are similar to the normal substrate. While non-competitive inhibitors are chemicals that bind to the enzyme and alter its shape. This renders the active site of the enzyme ineffective against the substrate. Tolerance makes a society that is fair and equitable.
Electronic items contain lcds
