A wheel of radius 0.5 m rotates with a constant angular speed about an axis perpendicular to its center. A point on the wheel th
1 answer:
Answer:
The tangential acceleration is 0 m/s².
Explanation:
Given:
Radius of the wheel = 0.5 m
The point of observation for calculating tangential acceleration = 0.2 m from center.
Tangential speed at the point of observation = 2 m/s
The angular speed of the wheel is a constant.
In order to determine the tangential acceleration, we make use of the following formula:
Tangential acceleration at a point = Angular acceleration × Distance of the point from center
Or,
Now, angular acceleration is defined as the rate of change of angular speed.
Here, the angular speed of the wheel is a constant. So, the change of angular speed is 0. Therefore, the angular acceleration is also 0 rad/s².
Now, from the above formula, as angular acceleration is 0, the magnitude of tangential acceleration at a point that is 0.2 m from the center of the wheel is also 0 m/s².
You might be interested in
Answer:
A. when the mass has a displacement of zero
Explanation:
The velocity of a mass on a spring can be calculated by using the law of conservation of energy. In fact, the total energy of the mass-spring system is equal to the sum of the elastic potential energy (U) of the spring and the kinetic energy (K) of the mass:
where
k is the spring constant
x is the displacement of the mass with respect to the equilibrium position of the spring
m is the mass
v is the velocity of the mass
Since the total energy E must remain constant, we can notice the following:
- When the displacement is zero (x=0), the velocity must be maximum, because U=0 so K is maximum
- When the displacement is maximum, the velocity must be minimum (zero), because U is maximum and K=0
Based on these observations, we can conclude that the velocity of the mass is at its maximum value when the displacement is zero, so the correct option is A.