Answer:
uhhh not really i don't even know what that is LOL
Answer:
[H₃O⁺] = 2.5 × 10⁻¹⁰ M
pH = 9.6
Explanation:
Step 1: Given data
Concentration of OH⁻ in the solution ([OH⁻]): 4.0 × 10⁻⁵ M
Step 2: Calculate the concentration of H₃O⁺ in the solution
Let's consider the self-ionization of water.
2 H₂O(l) ⇄ H₃O⁺(aq) + OH⁻(aq)
The <em>ion-product of water (Kw)</em> is:
<em>Kw = 1.0 × 10⁻¹⁴ = [H₃O⁺] × [OH⁻]</em>
[H₃O⁺] = 1.0 × 10⁻¹⁴/[OH⁻]
[H₃O⁺] = 1.0 × 10⁻¹⁴/4.0 × 10⁻⁵
[H₃O⁺] = 2.5 × 10⁻¹⁰ M
Step 3: Calculate the pH of the solution
We will use the following expression.
<em>pH = -log [H₃O⁺]</em>
pH = -log 2.5 × 10⁻¹⁰
pH = 9.6
Explanation:
please write full question
Answer:
The concentration of an acid in a solution can be determined by making an acid-base titration. To do this, a known volume of the acid solution is gradually added alkali solution whose concentration is known, until a neutral pH is reached.
Explanation:
Answer:
1.44 g/cm^3
Explanation:
The equation for density is d=m/v.