Question

During a titration experiment, a 150.0 mL solution of 0.05 M sulfuric acid (H₂SO₄) is neutralized by 300.0 mL solution with an unknown concentration of sodium hydroxide (NaOH). What is the concentration of the sodium hydroxide solution?

Answer 1

Answer: The concentration of the sodium hydroxide solution is 0.05 M

Explanation:

$H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O$

To calculate the concentration of the sodium hydroxide solution, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2SO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=0.05M\\V_1=150.0mL\\n_2=1\\M_2=?\\V_2=300.0mL$

Putting values in above equation, we get:

$2\times 0.05\times 150.0=1\times M_2\times 300.0\\\\M_2=0.05M$

Thus the concentration of the sodium hydroxide solution is 0.05 M