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Slav-nsk [51]
3 years ago
15

A tertiary source is the most desirable source for a researcher to use. True or false

Physics
1 answer:
Kaylis [27]3 years ago
6 0

The statement ‘A tertiary source is the most desirable source for a researcher to use’ is false. It should be that your source is primary because it is more reliable and is related to the research you have been working on.

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PROBLEM 5 (Problem 4-145 in 7th edition) Consider a well-insulated horizontal rigid cylinder that is divided into two compartmen
kari74 [83]

Answer:

The answer is "\bold{83.8^{\circ} \ C}".

Explanation:

Formula for calculating the mass in He:

\to m = \frac{PV}{RT}\\

        = \frac{500 \times 1}{ 2.0769 \times (40 + 273)}\\\\ = \frac{500 }{ 2.0769 \times 313}\\\\ = \frac{500 }{ 650.0697}\\\\= 0.76914 \ Kg

Formula for calculating the mass in N_2:

\to m = \frac{PV}{RT}\\

        = \frac{500 \times 1}{ 0.2968 \times (120+ 273)}\\\\ = \frac{500 }{ 0.2968 \times 393}\\\\ = \frac{500 }{ 116.6424}\\\\= 4.2866\ Kg

by using the temperature balancing the equation:

T' = \frac{mcT (He) + mcT ( N_2 )}{ mc (He) + mc ( N_2)}

    = \frac{0.76914 \times 3.1156 \times 313 + 4.2866 \times 0.743 \times393}{  0.76914 \times 3.1156 + 4.2866 \times 0.743} \\\\ = 357  \ \ K \approx  83.8^{\circ} \ C

3 0
3 years ago
How much energy is stored in a spring with a spring constant of 390 N/m if the spring is compressed a distance of 0.45 m from it
masya89 [10]
F=-ks
F=-(390)(.45)
F=-175.5 N

Work=force x displacement
Work= 175.5(0.45)
Work= 78.98 J

Work = ∆E =78.98 J

Answer=79J (first option)
4 0
3 years ago
An Olympic diver is on a diving platform 3.80 m above the water. To start her dive, she runs off of the platform with a speed of
AVprozaik [17]

Answer:

the diver's speed just before she enters the water is 8.718 m/s.

Explanation:

Given;

height of the diving platform, h = 3.8 m

initial velocity of the diver, u = 1.24 m/s

the diver's speed just before she enters the water is her final velocity, = v

Apply the following kinematic equation to determine the final velocity of the girl;

v² = u² + 2gh

v² = (1.24)² + 2(9.8 x 3.8)

v² = 76.018

v = √76.018

v = 8.718 m/s

Therefore, the diver's speed just before she enters the water is 8.718 m/s.

3 0
3 years ago
A force of 5.0 N moves a 6.0 kg object along a rough floor at a constant speed of 2.5 m/s. (a) How much work is done in 25 s.
Pavel [41]

Answer: ≈ 323 m

using Newton's 2nd law, we have:

F = ma

⇒ 5 = 6.a

⇔ a = 5/6 (m/s²)

the work done in 25s is S=2,5.25+\frac{25^{2} }{2}.\frac{5}{6} ≈ 323 (m)

Explanation:

6 0
3 years ago
An RLC series circuit consists of a 50 Ω resistor, a 200 μF capacitor, and a 120-mH inductor whose coil has a resistance of 20 Ω
solmaris [256]

Answer:

182.9 Volts

Explanation:

R = resistance of the resistor = 50 Ω

C = capacitance of the capacitor = 200 μF = 200 x 10⁻⁶ F

L = Inductance of the inductor = 120 mH = 0.12 H

f = frequency = 60 Hz

Capacitive reactance is given as

X = (2πfC)⁻¹

X = (2(3.14) (60) (200 x 10⁻⁶))⁻¹

X = 13.3 Ω

Inductive reactance is given as

X' = 2πfL

X' = 2(3.14) (60) (0.12)

X' = 45.2 Ω

Impedance of the circuit is given as

z = √(R² + (X' - X)²)

z = √(50² + (45.2 - 13.3)²)

z = 59.31 Ω

V = rms emf of the source = 240 Volts

rms voltage across the inductor is given as

V' = V z⁻¹ X'

V' = (240) (59.31)⁻¹ (45.2)

V' = 182.9 Volts

5 0
3 years ago
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