Answer:
heat; temperature; surrounding; insulated.
Explanation:
A calorimeter can be defined as a scientific instrument (device) that is designed and developed for measurement of the heat involved in chemical reactions or other processes, especially by taking the measurement of the temperature of the materials surrounding the process.
Basically, a calorimeter is insulated using materials with a very high level of resistivity, so as to prevent heat transfer to the outside of the device (calorimeter).
Some of the components that make up a simple calorimeter are; thermometer, an interior styrofoam cup, an exterior styrofoam cup, cover, etc.
Additionally, a calorie refers to the amount of heat required to raise the temperature of a gram of water by one degree Celsius (°C)
The answer is Decomposition.
No. For example, one rotation of the Earth takes 24 hours, one revolution around the sun takes 365.25 days, etc. This makes it very easy to create a standard system because no matter where you are in the world, this information stays the same.
Answer:
pH = 9.475
Explanation:
Hello there!
In this case, according to the basic ionization of the hydroxylamine:
![HONH_2+H_2O\rightarrow HONH_3^++OH^-](https://tex.z-dn.net/?f=HONH_2%2BH_2O%5Crightarrow%20HONH_3%5E%2B%2BOH%5E-)
The resulting equilibrium expression would be:
![Kb=\frac{[HONH_3^+][OH^-]}{[HONH_2]} =1.1x10^{-8}](https://tex.z-dn.net/?f=Kb%3D%5Cfrac%7B%5BHONH_3%5E%2B%5D%5BOH%5E-%5D%7D%7B%5BHONH_2%5D%7D%20%3D1.1x10%5E%7B-8%7D)
Thus, we first need to compute the initial concentration of this base by considering its molar mass (33.03 g/mol):
![[HONH_2]_0=\frac{1.34g/(33.03g/mol)}{0.500L} =0.0811M](https://tex.z-dn.net/?f=%5BHONH_2%5D_0%3D%5Cfrac%7B1.34g%2F%2833.03g%2Fmol%29%7D%7B0.500L%7D%20%3D0.0811M)
Now, we introduce
as the reaction extent which provides the concentration of the hydroxyl ions to subsequently compute the pOH:
![1.1x10^{-8}=\frac{x^2}{0.0811-x}](https://tex.z-dn.net/?f=1.1x10%5E%7B-8%7D%3D%5Cfrac%7Bx%5E2%7D%7B0.0811-x%7D)
However, since Kb<<<<1, it is possible to solve for
by easily neglecting it on the bottom to obtain:
![x=[OH^-]=\sqrt{1.1x10^{-8}*0.0811}= 2.99x10^{-5}](https://tex.z-dn.net/?f=x%3D%5BOH%5E-%5D%3D%5Csqrt%7B1.1x10%5E%7B-8%7D%2A0.0811%7D%3D%202.99x10%5E%7B-5%7D)
Thus, the pOH is:
![pOH=-log(2.99x10^{-5})=4.525](https://tex.z-dn.net/?f=pOH%3D-log%282.99x10%5E%7B-5%7D%29%3D4.525)
And the pH:
![pH=14-4.525\\\\pH=9.475](https://tex.z-dn.net/?f=pH%3D14-4.525%5C%5C%5C%5CpH%3D9.475)
Regards!