Add up 3+3=6, number has to be bigger than 9 so the answer is false.
I hope this helps you
5+1/3v=8-4
6/3v=4
2/v=4
v=2/4
v=1/2
blue with green is 5/10 green and red 3/10 both red 2/10 both blue 4/10
which means there is some integer
for which
.
Because
and
, there are integers
such that
and
, and
We have
, which means there are four possible choices of
:
1, 42
2, 21
3, 14
6, 7
which is to say there are also four corresponding choices for
:
9, 378
18, 189
27, 126
54, 63
whose sums are:
387
207
153
117
So the least possible value of
is 117.
For question 1)
During the 8-9 , Mr hare travel 40miles
For the time 9 onwards they travel concurrently,
Let x be the distance covered by both since they can only meet if they covered the sams distance,
x/50 = x/40 -1 ,where the 1 is the (8-9) 1 hr
x/40 - x/50 = 1
x = 200
Time take by Mr Hare = 200/ 40 = 5
from 8 add 5 hours will be 1
ans is b
2)
during 8- 9 hare travelled 50miles
let x be the distance
x/55= x/50-1
x/50-x/55=1
x=550miles
time taken by hare = 550/50=11 hr
ie when they first meet it will be 7pm
so ans is b 8