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kupik [55]
3 years ago
13

PLZ HELP

Mathematics
2 answers:
shepuryov [24]3 years ago
6 0
Reflecting the X axis flips to the left or right. -3 would become positive 3. The answer is (3, 7)
Gala2k [10]3 years ago
4 0
3 and -7 would be the answer
You might be interested in
HELP ASAP FOR BRAINLIEST:
Fed [463]

Answer: 228 students

Step-by-step explanation:

Since the results for the standardized test are normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = test reults

µ = mean score

σ = standard deviation

From the information given,

µ = 1700 points

σ = 75 points

We want to find the probability of students expected to score above 1850 points. It is expressed as

P(x > 1850) = 1 - P(x ≤ 1850)

For x = 1850,

z = (1850 - 1700)/75 = 150/75 = 2

Looking at the normal distribution table, the probability corresponding to the z score is 0.97725

P(x > 1850) = 1 - 0.97725 = 0.02275

If 10,000 students take the exam, then the number of students you would expect to score above 1850 points is

0.02275 × 10000 = 228 students

7 0
3 years ago
the old price for school lunches is $5. The new price is $5.25. What is the percent increase in the cost if school lunches? Writ
Elanso [62]

p = 5.25-5.00/5.00

p =0.25/5.00

p=0.05 = 5% increase

5 0
3 years ago
A train moves from rest to a speed of 40 m/s in 20.0 seconds. What is its acceleration?
alina1380 [7]

Answer: 25m/s

Explanation:

S1=(2u+v)t   \\ =20×20=400m \\ S2=40×20=800m \\ S3=(2u+v)t \\ =20×40=800m \\ Total \:  displacement =2000 m \\ Total  \: time \:  taken =80 m \\ V=802000=25m/s

5 0
4 years ago
This is for pre-calc can someone pls help
stepladder [879]

Answer:

Question 18: 453,600

Step-by-step explanation:

4 0
3 years ago
How many ways are there to put 6 balls in 3 boxes if three balls are indistinguishably white, three are indistinguishably black,
erik [133]
Let the boxes be Box 1, Box 2, Box 3. 

consider the 3 white balls. They can be all of them in one box:

(3, 0, 0) (3 in Box 1, 0 in box 2 and 0 in box 0)
(0, 3, 0)
(0, 0, 3)

We can have 2 in one box, and 1 in one of the remaining boxes:

(2, 0, 1)
(2, 1, 0)
(0, 2, 1)
(1, 2, 0)
(0, 1, 2)
(1, 0, 2)

and there is only one way: (1, 1, 1) to place one white ball in each box

In total there are: 3+6+1=10 ways to place the white balls. Similarly there are 10 ways to place the black ones.

Since every placement of the white balls can be combined with any placement of the black balls, there are 10*10=100 ways to place the 3white balls and the 3 black bals in the boxes.


Answer: 100
4 0
3 years ago
Read 2 more answers
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