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azamat
3 years ago
8

A person with mass mp = 76 kg stands on a spinning platform disk with a radius of R = 1.98 m and mass md = 191 kg. The disk is i

nitially spinning at ω = 1.7 rad/s. The person then walks 2/3 of the way toward the center of the disk (ending 0.66 m from the center).
If the person now walks back to the rim of the disk, what is the final angular speed of the disk?
Physics
1 answer:
nalin [4]3 years ago
3 0
<span>1.7 rad/s The key thing here is conservation of angular momentum. The system as a whole will retain the same angular momentum. The initial velocity is 1.7 rad/s. As the person walks closer to the center of the spinning disk, the speed will increase. But I'm not going to bother calculating by how much. Just remember the speed will increase. And then as the person walks back out to the rim to the same distance that the person originally started, the speed will decrease. But during the entire walk, the total angular momentum remained constant. And since the initial mass distribution matches the final mass distribution, the final angular speed will match the initial angular speed.</span>
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2 years ago
A large lightning bolt is observed to have a 19500 A current and move 36 C of charge. What was its duration?
Lynna [10]

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Its duration is 1.85*10⁻³ s or 1.85 ms

Explanation:

The intensity of electric current I is defined as the amount of electric charge Q (measured in Coulombs) that passes through a section of a conductor in each unit of time. The letter I is used to name the Intensity and its unit is the Ampere (A).

The intensity of electric current is expressed as:

I=\frac{Q}{t}

where:

I: Intensity expressed in Amps (A)

Q: Electric charge expressed in Coulombs (C)

t: Time expressed in seconds (s)

Being:

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Replacing:

19500 A=\frac{36 C}{t}

Solving:

19500 A*t= 36 C

t=\frac{36 C}{19500 A}

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<u><em>Its duration is 1.85*10⁻³ s or 1.85 ms</em></u>

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3 years ago
When sugar is poured from the box into the sugar bowl, the rubbing of sugar grains creates a static electric charge that repels
Afina-wow [57]

Answer:

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From the question,

since q' = q

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F = kq²/r²..................... Equation 2

Given: q = 1.79×10⁻¹¹ C, r = 3.45×10⁻⁵ m,

Constant: k = 9×10⁹ Nm²/kg².

Substitute into equation 2

F = 9×10⁹(1.79×10⁻¹¹)²/(3.45×10⁻⁵ )²

F = 9×10⁹(3.2041×10⁻²²)/(11.9025×10⁻¹⁰)

F = (28.8369×10⁻¹³)/(11.9025×10⁻¹⁰)

F = 2.6×10⁻³ N.

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3 years ago
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