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Kisachek [45]
3 years ago
15

A swimmer is swimming to the left with a speed of 1.0\,\dfrac{\text m}{\text s}1.0 s m ​ 1, point, 0, start fraction, start text

, m, end text, divided by, start text, s, end text, end fraction when she starts to speed up with constant acceleration. The swimmer reaches a final speed of 2.5\,\dfrac{\text m}{\text s}2.5 s m ​ 2, point, 5, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction over a distance of 5.0\,\text m5.0m5, point, 0, start text, m, end text. How long did the swimmer take to speed up to 2.5\,\dfrac{\text m}{\text s}2.5 s m ​ 2, point, 5, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction?
Physics
2 answers:
bulgar [2K]3 years ago
3 0

Answer:

2.9s

Explanation:

galina1969 [7]3 years ago
3 0

Answer:

2.9s

Explanation:

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Your own car has a mass of 2000 kg. If your car produces a force of 5000 N, how fast will it accelerate?
Sidana [21]

Answer:

2.5m/s²

Explanation:

Given parameters:

Mass of car  = 2000kg

Force produced by the car  = 5000N

Unknown:

Acceleration of the car  = ?

Solution:

According to Newton's second law of motion, Force is a product of mass and acceleration.

  Force  = mass x acceleration

Now, insert the parameters and find the unknown;

  5000 = 2000 x acceleration

   Acceleration  = \frac{5000}{2000}   = 2.5m/s²

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Explanation:

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(a) Calculate the magnitude of the gravitational force exerted by Mars on a 80 kg human standing on the surface of Mars. (The ma
andrew11 [14]

Answer:

a) F=1.044\times 10^9\ N

b)F'=1.044\times 10^9\ N

c) F_p=1.0672\times10^{-7}\ N

d) Treat the humans as though they were points or uniform-density spheres.

Explanation:

Given:

  • mass of Mars, M=6.4\times 10^{23}\ kg
  • radius of the Mars, r=3.4\times 10^{6}\ m
  • mass of human, m=80\ kg

a)

Gravitation force exerted by the Mars on the human body:

F=G.\frac{M.m}{r^2}

where:

G=6.67 \times 10^{-11}\ m^3.kg^{-1}.s^{-2} = gravitational constant

F=6.67\times10^{-11}\times \frac{6.4\times 10^{23}\times 80}{(3.4\times 10^{6})^2}

F=1.044\times 10^9\ N

b)

The magnitude of the gravitational force exerted by the human on Mars is equal to the force by the Mars on human.

F'=F

F'=1.044\times 10^9\ N

c)

When a similar person of the same mass is standing at a distance of 4 meters:

F_p=6.67\times10^{-11}\times \frac{80\times 80}{4}

F_p=1.0672\times10^{-7}\ N

d)

The gravitational constant is a universal value and it remains constant in the Universe and does not depends on the size of the mass.

  • Yes, we have to treat Mars as spherically symmetric so that its center of mass is at its geometric center.
  • Yes, we also have to ignore the effect of sun, but as asked in the question we have to calculate the gravitational force only due to one body on another specific body which does not brings sun into picture of the consideration.
4 0
3 years ago
A ball is thrown off the top of a building and lands on the ground below.
natita [175]

Answer:

Mass and velocity.

Explanation:

Kinetic energy <u>is the energy that an object has due to its movement</u>, mathematically it is represented as follows:

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where m is the mass of the object, and v is its velocity at a given point in time.

So we can see that to find the kinetic energy just before the ball hits the gound, we need the quantities:

  • mass of the ball
  • velocity of the ball before it hits the ground

With the knowledge of these two quantities the kinetic energy of the ball  before touching the gound can be determined.

4 0
3 years ago
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