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zysi [14]
3 years ago
9

How many moles are in 3.113 g of Au?Molar mass of Au=197 g/mol

Chemistry
1 answer:
SVEN [57.7K]3 years ago
3 0
<h3>Answer:</h3>

0.0157 g Au

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right
<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.113 g Au

<u>Step 2: Identify Conversions</u>

Molar Mass of Au - 197.87 g/mol

<u>Step 3: Convert</u>

<u />3.113 \ g \ Au(\frac{1 \ mol \ Au}{197.87 \ g \ Au} ) = 0.015733 g Au

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

0.015733 g Au ≈ 0.0157 g Au

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Answer:

Chlorine (Cl)

Explanation:

The equation would be:

F+NaCl  → NaF + Cl

This is because no atom is lost in a reaction. Chlorine would be the missing chemical as it is on the other side of the equation and needs to be accounted for on the products side.

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Two students make a model of a tree house they want to build. the scale is 1:42 in the scale model the tree house door is 3 cm t
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Two 10g blocks, one of copper and one of iron, were heated from 300 K to 400K (a temperature difference of 100 K).
vova2212 [387]

Energy absorbed by Iron block E (iron) = 460.5 J

Energy absorbed by Copper block E (Copper) = 376.8 J

<u>Explanation:</u>

To find the heat absorbed, we can use the formula as,

q = m c ΔT

Here, Mass = m = 10 g = 0.01 kg

ΔT = change in temperature = 400 - 300 = 100 K = 100 - 273 = -173 °C

c = specific heat capacity

c for iron = 460.5 J/kg K

c for copper = 376.8 J/kg K

Plugin the values in the above equation, we will get,

q (iron) = 0.01 kg × 460.5 J/kg K × 100 K

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q (copper) = 0.01 kg ×  376.8 J/kg K × 100 K

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3 0
3 years ago
Is 6.0 × 10 to the negative 4th power is a significant figure?​
Dmitry_Shevchenko [17]

Answer:

Yes

Explanation:

First remember that a significant figure are basically values that contribute to the precision of a value. In any scientific notation the values are significant figures because these values stay the same. In this case we have two significant figures which is 6 and 0, you can further prove that they are significant figures by converting the notation into standard form.

6.0\times10^{-4}

Negative so move the decimal point to the left:

=0.00060

6 and 0 are the significant figures in this standard notation because it's precise to it's actual value which is 6.0.

To sum up, the values you have on the left side of a notation are significant figures since they will not change no matter if it's standard or scientific notation meaning it's precise.

Hope this helps.

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2 years ago
Which describes the molecule shown below?
attashe74 [19]
I think the b is right ( Saturated Alkyne)
6 0
2 years ago
Read 2 more answers
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