First we need to find the number of moles of hydrogen gas formed
Zn + 2HCl ---> ZnCl₂ + H₂
stoichiometry of Zn to H₂ is 1:1
the number of Zn moles reacted - 2.4 g / 65.4 g/mol = 0.0367 mol
assuming Zn to be the limiting reactant
number of Zn moles reacted = number of H₂ moles formed
therefore number of H₂ moles formed = 0.0367 mol
we can use ideal gas law equation to find the pressure
PV = nRT
P - pressure
V - Volume - 450 x 10⁻⁶ m³
n - number of moles - 0.0367 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 32 °C + 273 = 305 K
substituting these values in the equation
P x 450 x 10⁻⁶ m³ = 0.0367 mol x 8.314 Jmol⁻¹K⁻¹ x 305 K
P = 206.8 kPa
pressure is 206.8 kPa
Answer:
The reaction would take place with racemization.
Explanation:
The compound (R)-3-bromo 3-methylhexane contains has the leaving group attached to a tertiary carbon atom. When the leaving group is attached to a tertiary carbon atom, the compound undergoes nucleophilic substitution via SN1 mechanism. This mechanism involves the formation of a planar carbocation intermediate. The nucleophile may attack this intermediate from either faces, leading to racemization of the product.
Answer:
Amount of salt needed is around 2.3*10³ g
Explanation:
The salt content in sea water = 3.5 %
This implies that there is 3.5 g salt in 100 g sea water
Density of seawater = 1.03 g/ml
Volume of seawater = volume of tank = 62.5 L = 62500 ml
Therefore, the amount of seawater required is:

The amount of salt needed for the calculated amount of seawater is:

Answer:
One mole of cadmium (6multiply1023 atoms) has a mass of 112 grams, as shown in the periodic table on the inside front cover of the textbook. The density of cadmium is 8.65 grams/cm3.
Explanation: