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Yanka [14]
3 years ago
13

Hakeem was dismayed to discover that he offended coworkers by standing 2 feet away from them during business conversations. In t

he U.S., what distance would have been more appropriate? PS 2100
Physics
1 answer:
Eddi Din [679]3 years ago
3 0

Personal space differs from culture to culture, though it is widely acknowledged that Europe and U.S have bigger personal space requirements that their counterparts in Asia.

Hakeem might not realize it but it’s commonly accepted for Americans to have a distance between four to twelve feet between one another in social settings, especially in professional ones. A distance of two feet is only acceptable if the individual is part of the person’s inner circle, such as friends and family.  

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Compare the Vf calculated at the point of impact to the horizontal velocity you calculated using Δx and Δy. Were the vf and the
34kurt

Answer: Velocities are not equal

Explanation: A projectile usually have a given initial velocity, the velocity must be resolve into components of x and y with respect to the velocity of the projectile in a certain angle. In a projectile trajectory the final velocity for the y- component is always 0m/s since the object reaches its maximum point.

4 0
3 years ago
¿Qué resistencia debe ser conectada en paralelo con una de 20 Ω para hacer una
Lisa [10]

Answer:

La resistencia que debe ser conectada en paralelo con una de 20 Ω para hacer una  resistencia combinada de 15 Ω tiene un valor de 60 Ω

Explanation:

Las resistencias son aquellos dispositivos en los circuitos eléctricos que suelen emplearse para oponerse al paso de la corriente eléctrica.

Se denomina resistencia resultante o equivalente al valor de la resistencia que se obtiene al considerar un conjunto de ellas.

Cuando tenes resistencias en paralelo la corriente se divide y circula por varios caminos.

La resistencia equivalente de un circuito de resistencias en paralelo es igual al recíproco de la suma de los inversos de las resistencias individuales:

R=\frac{1}{\frac{1}{R_{1} } +\frac{1}{R_{2} } +...+\frac{1}{R_{N} }}

Esto también puede ser expresado como:

\frac{1}{R} =\frac{1}{R_{1} } +\frac{1}{R_{2} } +...+\frac{1}{R_{N} }

Entonces, en este caso sabes:

  • R= 15 Ω
  • R1= 20 Ω
  • R2=?

Reemplazando:

\frac{1}{15} =\frac{1}{20}+\frac{1}{R2}

y resolviendo:

\frac{1}{R2} =\frac{1}{15} -\frac{1}{20}

\frac{1}{R2} =\frac{1}{60}

se obtiene:

R2=60 Ω

<u><em>La resistencia que debe ser conectada en paralelo con una de 20 Ω para hacer una  resistencia combinada de 15 Ω tiene un valor de 60 Ω</em></u>

6 0
3 years ago
If you push on a heavy box that is at rest, you must exert some force to start its motion. 5. however, once the box is in motion
Free_Kalibri [48]
The potential energy has turned into kinetic energy and energy is not lost on the box, some is lost to friction, but most of it is still kept.
5 0
3 years ago
Using the balanced chemical equation below, calculate how many moles of ammonia would be produced when 9.1 moles of hydrogen gas
strojnjashka [21]

6.07 moles

Explanation:

Given parameters:

Number of moles of reacting hydrogen gas = 9.1 moles

Unknown:

Number of moles of ammonia produced = ?

Solution:

  Balanced chemical equation:

           N₂   +     3H₂    →      2NH₃

We should work from the known to the unknown specie. We known the number of moles of hydrogen gas reacting. We simply relate this to that of the ammonia.

 From the reaction:

   3 mole of hydrogen gas produced 2 mole of ammonia

     9.1 moles of the hydrogen gas will produce:  \frac{2 x 9.1}{3}

                                                                            = 6.07 moles

Learn more:

Number of moles brainly.com/question/1841136

#learnwithbrainly

3 0
3 years ago
An intravenous (IV) system is supplying saline solution to a patient at the rate of 0.06 cm3/s through a needle of radius 0.2 mm
horsena [70]

Answer:

Pressure applied to the needle is 7528 Pa

Explanation:

As we know by poiseuille's law of flow of liquid through a cylindrical pipe

the rate of flow through the pipe is given as

Q = \frac{\Delta P \pi r^4}{8\eta L}

now we know that

Q = 0.06 \times 10^{-6} m^3/s

radius = 0.2 mm

Length = 6.32 cm

\eta = 1\times 10^{-3} Pa s

now we have

6 \times 10^{-8} = \frac{\Delta P \pi (0.2 \times 10^{-3})^4}{8(1 \times 10^{-3})6.32 \times 10^{-2}}

3.03 \times 10^{-11} = \Delta P 5.02 \times 10^{-15}

\Delta P = 6028 Pa

now we have

P - 1500 = 6028 Pa

P = 7528 Pa

8 0
3 years ago
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