Answer:
as its mass and velocity will less so its momentum will be less than that of baseball
<span>The electric force is given by:
F = [ k*(q1)*(q2) ] / d^2
F = Electric force
k = Coulomb's constant
q1 = Charge of one proton
q2 = Charge of second proton
d = Distance between centers of mass
Values:
F = unknown
k = 8.98E 9 N-m^2/C^2
q1 = 1.6E-19
q2 = 1.6E-19
d = 1.0E-15 m
Insert values into F = [ k*(q1)*(q2) ] / d^2
F = [ (8.98E 9 N-m^2/C^2) * (1.6E-19) * (1.6E-19) ] / (1.0E-15 m)^2
F = </span>229.888 N
answer
the electric force of repulsion between nuclear protons is 229.888 N
Answer:
0.2 m
Explanation:
PHASE 1
First, we calculate the distance the tongue moved in the first 20 ms (0.02 secs). We use one of Newton's equations of linear motion:
where u = initial velocity = 0 m/s
a = acceleration = 
t = time = 0.02 s
Therefore:
PHASE 2
Then, for the next 30 ms (0.03 secs), we use the formula:
This speed is the same as the final velocity of the tongue after the first 20 ms.
This can be obtained by using the formula:
Therefore:
distance = 5 * 0.03 = 0.15 m
Therefore, the total distance moved by the tongue in the 50 ms interval is:
0.05 + 0.15 = 0.2 m
Answer:
The energy which is produced by a battery is 101.1 kJ.
Explanation:
The expression for the energy in terms of voltage, current and time is as follows;
E=VIt
Here, V is the voltage, I is the current and t is the time.
It is given in the problem that a battery can provide a current of 1.80 A at 2.60 V for 6.00 hr.
Calculate the energy of the battery.
E=VIt
Convert time from hour int seconds.
t=6 hr
t=(6)(60)(60)
t=21600 s
Put I= 1.80 A, V= 2.60 V and t= 21600 s in the expression of energy.
E=(2.60)(1.80)(21600)
E= 101.1 kJ
Therefore, the energy which is produced by a battery is 101.1 kJ.
