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nexus9112 [7]
3 years ago
15

Sliced or pulled golf driffed from its intended path explain from Bernaulli's principle​

Physics
1 answer:
Inessa [10]3 years ago
7 0

Answer:

プルまたはゴルフがベルナウリの原理を引き裂いた

Explanation:

読めませんか?

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While on an ice-fishing trip, you find yourself holding a 10 kg fish but stuck in the middle of
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The forward force you exert on the fish and your backward action will allow you to reach the shore.

<h3>Newton's third law of motion</h3>

Newton's third law of motion states that for every action, there is an equal and opposite reaction.

Fa = -Fb

Let's assume the fish is held in the hook, this will give you the opportunity to throw the fish forward while still holding it.

When the the fish is thrown forward, you will move backwards with an equal force based on Newton's third law. Your backward momentum towards the shore will help to maintain equal linear momentum between you and the fish.

Thus, this forward force of the fish and your backward action will allow you to reach the shore.

Learn more Newton's third law of motion here: brainly.com/question/25998091

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2 years ago
James weighs 67 pounds on Earth. He has a mass of 30 kilograms. Which of the following is true?
morpeh [17]

Answer:

I think its B. James would have a smaller mass on the Moon than he does on Earth.

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A 70kg man is moving with a speed of 3.2 m/s on a rough surface, his speed was decreasing uniformly until he reaches to a stop b
VMariaS [17]

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224 N

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Preschool girls and boys do not differ in the amount of muscle they have<br> 1) True<br> 2) False
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In a game of basketball, a forward makes a bounce pass to the center. The ball is thrown with an initial speed of 4.8 m/s at an
tensa zangetsu [6.8K]
The equation to be used here is the trajectory of a projectile as written below:

y = xtanθ +/- gx²/2v²(cosθ)²
where
y is the vertical distance
x is the horizontal distance
θ is the angle of trajectory or launch angle
g is 9.81 m/s²
v is the initial velcity

Since the angle is below horizontal, let's use the minus equation. Substituting the values:

- 0.8 m = xtan15° - (9.81 m/s²)x²/2(4.8 m/s)²(cos15°)²
Solving for x,
x = 2.549 m

However, we only take half of this distance because it was specified that the distance asked before bouncing. Hence, the horizontal distance is equal to 1.27 m.
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3 years ago
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