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anzhelika [568]
2 years ago
9

The y component of a vector is 36, and the angle between the vector and the x axis is 27 what is the magnitude of the vector

Physics
1 answer:
xz_007 [3.2K]2 years ago
3 0

Answer:

Magnitude of Vector = 79.3

Explanation:

When a vector is resolved into its rectangular components, it forms two vector components. These components  are named as x-component and y-component, they are calculated by the following formulae:

x-component of vector = (Magnitude of Vector)(Cos θ)

y-component of vector = (Magnitude of Vector)(Sin θ)

where,

θ = angle of the vector with x-axis = 27°

Therefore, using the values in the equation of y-component, we get:

36 = (Magnitude of Vector)(Sin 27°)

Magnitude of Vector = 36/Sin 27°

<u>Magnitude of Vector = 79.3</u>

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Explanation:

Given:

- y (x, t) = 8.50*cos(172*x -2730*t)

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Find:

The attached weight W given that Tension and W are equal.

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                            y (x, t) = A*cos(k*x -w*t)  

Where k = stiffness and w = angular frequency

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                            T = Y*V^2

where Y: is the mass per unit length of the string.

- The tension T and weight attached W are equal:

                           T = W = Y*V^2 = (w/L*g)*V^2

                            W = (0.0126 / 1.8*9.81)*(13.78)^2

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