Answer:
The answer to your question is: water, polar solvent.
Explanation:
Data
sample of CaCl2
Solid copper this option is incorrect because in order to dissolve something the solvent must be liquid and this is a solid solvent.
water, I think this option is right, because CaCl2 is ionic and water is a polar solvent, CaCl2 will dissolve in water.
a polar solvent, CaCl2 will dissolve is a polar solvent like water, this option is correct.
hexane, CaCl2 will not dissolve in hexane because hexane is a non polar solvent and CaCl2 is ionic. This option is wrong
a nonpolar solvent This option is not right, CaCl2 will only dissolve in polar solvents.
liquid mercury, This option is wrong, mercury is not a solvent.
I'd say conduction maybe I'm honestly not sure bc it has nothing to do with radiation so its between conduction and convection cause id guess they wouldn't want the heat to escape so it wouldn't be convection ???
Answer : The mass of vanadium(V) oxide will be 
Explanation : Given,
Number of atoms of
= 
Molar mass of
= 181.88 g/mole
In
, there are 2 atoms of vanadium and 5 atoms of oxygen.
First we have to determine the moles of
.
As,
number of vanadium atom present in 1 moles of 
So,
number of vanadium atom present in
moles of 
Now we have to determine the mass of
.


Therefore, the mass of vanadium(V) oxide will be 
Answer:
λ = 5.56 × 10⁻³ m
Explanation:
You have to use the formula c = λv to solve the problem. Review what you are given. You are given v and c, where v = 5.40 × 10¹⁰ Hz and c = 3.00 × 10⁸ m/s. The value c is for the speed of light and is something you need to memorize. You will use it often in physics and sometimes in chemistry.
Now that you figured out what you know, you can see that there is only one unknown, allowing you to solve.
c = λv
λ = c/v
λ = (3.00 × 10⁸ m/s)/(5.40 × 10¹⁰ Hz)
λ = 5.56 × 10⁻³ m
Answer:
All rocks have same thermal conductivity.
Explanation:
Rocks are heated with the sunlight exposure. Different types of rocks have different thermal conductivity. The heat energy of the rocks is measure in Joules. The size and thermal conductivity of the rocks is important property which determines their heating capacity.