1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Eva8 [605]
2 years ago
15

A fish finder uses a sonar device that sends 20,000-Hz sound pulses downward from the bottom of the boat, and then detects echoe

s. Part A If the maximum depth for which it is designed to work is 230 m , what is the minimum time between pulses (in fresh water)
Physics
1 answer:
mrs_skeptik [129]2 years ago
3 0

Answer:  The minimum time between pulses (in fresh water)

= 0.3106 s

Explanation:

To calculate the speed of echoes sounds, we will use

Speed = 2x/t

Where x = distance and t = total time.

Please note that:

sound travels at 343 m/s in air. But it travels at 1,481 m/s in water (almost 4.3 times as fast as in air); 

Total distance = 2 × 230 = 460m

Using speed of sound in water

1481 = 460/t

t = 460/1481

t = 0.3106

You might be interested in
A spectroscope prism separates the white light from a star into a very wide spectrum. When widely spread, black lines appear in
topjm [15]

Answer:

C. It helps scientists detect dark matter.

Explanation:

I got a 100% on my test. hope it help and I hope your having an awesome day :)

5 0
2 years ago
Read 2 more answers
Jamal plugged his radio into the wall. The radio's plug had copper wires surrounded by rubber. The rubber protects Jamal from___
Mariana [72]
The rubber protects him from being electrocuted by the flow of current going through the plug.
Hope this helped!!
3 0
3 years ago
Read 2 more answers
A block of mass m=1.2 kg is held at rest against a spring with a force constant k=730N/m. Initially the spring is compressed a d
igor_vitrenko [27]

Answer:

Explanation:

potential energy of compressed spring

= 1/2 k d²

= 1/2 x 730 d²

= 365 d²

This energy will be given to block of mass of 1.2 kg in the form of kinetic energy .

Kinetic energy after crossing the rough patch

= 1/2 x 1.2 x 2.3²

= 3.174 J

Loss of energy

= 365 d² - 3.174  

This loss is due to negative work done by frictional force

work done by friction = friction force x width of patch

= μmg d ,   μ = coefficient of friction , m is mass of block , d is width of patch

= .44 x 1.2 x 9.8 x .05

= .2587 J

365 d² - 3.174   = .2587

365 d² = 3.4327

d² = 3.4327 / 365

= .0094

d = .097 m

= 9.7 cm

If friction increases , loss of energy increases . so to achieve same kinetic energy , d will have to be increased so that initial energy increases so compensate increased loss .

5 0
3 years ago
A thin double convex glass lens with an index of 1.56 while surrounded by air has a 10 cm focal length. If it is placed under wa
bearhunter [10]

Explanation:

Formula which holds true for a leans with radii R_{1} and R_{2} and index refraction n is given as follows.

          \frac{1}{f} = (n - 1) [\frac{1}{R_{1}} - \frac{1}{R_{2}}]

Since, the lens is immersed in liquid with index of refraction n_{1}. Therefore, focal length obeys the following.  

            \frac{1}{f_{1}} = \frac{n - n_{1}}{n_{1}} [\frac{1}{R_{1}} - \frac{1}{R_{2}}]  

             \frac{1}{f(n - 1)} = [\frac{1}{R_{1}} - \frac{1}{R_{2}}]

and,       \frac{n_{1}}{f(n - n_{1})} = \frac{1}{R_{1}} - \frac{1}{R_{2}}

or,          f_{1} = \frac{fn_{1}(n - 1)}{(n - n_{1})}

              f_{w} = \frac{10 \times 1.33 \times (1.56 - 1)}{(1.56 - 1.33)}

                          = 32.4 cm

Using thin lens equation, we will find the focal length as follows.

             \frac{1}{f} = \frac{1}{s_{o}} + \frac{1}{s_{i}}

Hence, image distance can be calculated as follows.

       \frac{1}{s_{i}} = \frac{1}{f} - \frac{1}{s_{o}} = \frac{s_{o} - f}{fs_{o}}

              s_{i} = \frac{fs_{o}}{s_{o} - f}

             s_{i} = \frac{32.4 \times 100}{100 - 32.4}

                       = 47.9 cm

Therefore, we can conclude that the focal length of the lens in water is 47.9 cm.

4 0
3 years ago
An object initially at rest experiences an acceleration of 9.8 m/s2. How much time will it take to achieve a velocity of 58 m/s?
frez [133]
5.91(approx) seconds just divide velocity by acceleration
4 0
3 years ago
Other questions:
  • a toy car moves around a loop-the-loop track.The loop is 0.5 high.What is the minimum speed of the car at the top of the loop fo
    9·1 answer
  • The fastest growing plant on record is the Hesperoyucca whipplei. Suppose a plant of this type grows 3.7 m in 14 days. What is i
    5·1 answer
  • Unpolarized light is incident upon two polarization filters that do not have their transmission axes aligned. If 38 % of the lig
    7·1 answer
  • consider two charges. one has a charge of +15.mC and the other a charge of -3.00mC. if the electrostatic force between these cha
    6·1 answer
  • A man standing on a bus remains still when the bus is at rest. When the bus moves forward and then slows down the man continues
    13·2 answers
  • 8. If Bulb 8 burns out, how will the remaining bulbs be affected?
    15·1 answer
  • Use of lubricants increase efficency of machine​
    6·1 answer
  • A) Khi nào một vật được coi là chuyển động ? Cho ví dụ ?
    5·1 answer
  • Images help to convey information that might sometimes be very complex if explained in words. Images also simplify certain expla
    8·1 answer
  • An object, which is at the origin at time t=0
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!