A cylinder within a piston expands from a volume of 1.00 L to a volume of 2.00 L against an external pressure of 1.00 atm. How m
1 answer:
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Answer:
Explanation:
Given parameters:
Weight of object = 49N
Force applied = 12N
Unknown:
Acceleration of object = ?
Solution:
The acceleration of the object is found by dividing the force by the weight;
Acceleration = = 0.25m/s²
Answer:
Refer to the attachment for solution (1).
<h3><u>Calculating time taken by it to stop (t) :</u></h3>By using the second equation of motion,
→ v = u + at
- v denotes final velocity
- u denotes initial velocity
- t denotes time
- a denotes acceleration
→ 0 = 5 + (-5/6)t
→ 0 = 5 - (5/6)t
→ 0 + (5/6)t = 5
→ (5/6)t = 5
→ t = 5 ÷ (5/6)
→ t = 5 × (6/5)
→ t = 6 seconds
→ Time taken to stop = 6 seconds
