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dangina [55]
3 years ago
10

A cylinder within a piston expands from a volume of 1.00 L to a volume of 2.00 L against an external pressure of 1.00 atm. How m

uch work (in Joule) was done by the expansion?
Physics
1 answer:
UkoKoshka [18]3 years ago
6 0

Answer:

1.671L

Explanation:

In the given case the pressure is constant therefore it is an isobaric process, the process in which the pressure remains constant is called as isobaric process.

Work done= external pressure× change in volume.

288= 2×( final volume-intial volume)×101.32

144÷101.32=(finalvolume-0.250)

1.421=final volume-0.250

final volume=1.671L

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Answer:

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Explanation:

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(a) What is the minimum width of a single slit (in multiples of λ ) that will produce a first minimum for a wavelength λ ? (b) W
Kitty [74]

Answer:

The minimum value of width for first minima is λ

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Explanation:

Given that,

Wavelength = λ

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We need to calculate the minimum width

Using formula of minimum width

D\sin\theta=n\lambda

D=\dfrac{n\lambda}{\sin\theta}

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\lambda = wavelength

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D=\dfrac{n\lambda}{\sin\theta}

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D=\dfrac{1\times\lambda}{1}

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D=\dfrac{50\times\lambda}{1}

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D=\dfrac{1000\times\lambda}{1}

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3 years ago
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yanalaym [24]

Answer:

A. If the sum of the external forces on an object is zero, then the object must be in equilibrium

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