A cylinder within a piston expands from a volume of 1.00 L to a volume of 2.00 L against an external pressure of 1.00 atm. How m uch work (in Joule) was done by the expansion?
1 answer:
Answer:
1.671L
Explanation:
In the given case the pressure is constant therefore it is an isobaric process, the process in which the pressure remains constant is called as isobaric process.
Work done= external pressure× change in volume.
288= 2×( final volume-intial volume)×101.32
144÷101.32=(finalvolume-0.250)
1.421=final volume-0.250
final volume=1.671L
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