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gizmo_the_mogwai [7]
3 years ago
13

A small compass is placed near a very large piece of ferromagnetic material. Before the compass is placed near the material, it

is pointing toward the Earth’s geographic north. Would the compass needle move? Explain your reasoning. If so, what direction would it point? Explain your reasoning.
Physics
1 answer:
NeTakaya3 years ago
7 0

Answer:

it will move towards the object's magnetic south

Explanation:

The compass pints towards the earth geographic north because the magnetic south of the earth's magnetic field is located in there, if you placed such compass neaar the piece of ferromagnetic material, the magnetic field produced by the magnet will make the compass needle point towards its south magnetic pole, in the same fashion as it points to the earth's magnetic south. It will point to the object's south pole because the magnetic field will be stronger than the earth's (which is weak) that is because of the way magnetism works, opposite poles are attracted and similar poles will tend to separate from each other

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Arada [10]

Answer:

Radiation

Explanation:

Radiation refers to the emission of energy in rays or waves

8 0
3 years ago
high school physics, no need detail explain, just give the answer, but you have to make sure thank you
andrey2020 [161]

Answer:

approximately 30 degrees

Explanation:

If it takes the cannonball 2 seconds to reach the maximum height, we can use the analysis of the vertical component of the velocity and the fact that the acceleration of gravity is the one acting opposite to this initial vertical component (v_y) of the velocity. We know as well that at the top of the trajectory, the vertical component of the velocity is zero, and then the movement starts going down in it trajectory. So, the final velocity for the first part of the ascending movement is zero, giving us the following equation for the velocity under an accelerated movement (with acceleration of gravity "g" acting):

v_f=v_i-a\,t\\v_f=v_y-g\,t\\0=v_y-9.8\,*\,2\\v_y=9.8\,*\,2=19.6 \frac{m}{s}

By knowing the vertical component of the initial velocity (19.6 m/s), and the actual magnitude of the total initial velocity (40 m/s), we can calculate what angle was the initial velocity vector forming above the horizontal. We use for such the fact that the sine of the angle relates the opposite side of a right angle triangle with the hypotenuse, and solve for the angle using the arcsin function:

sin(\theta)=\frac{opp}{hyp} \\sin(\theta)=\frac{19.6}{40}\\\theta=arcsin(\frac{19.6}{40})\\\theta=29.34^o

which tells us that the closer answer shown is 30^o

7 0
3 years ago
Select the correct answer.
soldi70 [24.7K]

Answer:

OD. The process of cutting down irrelevant information so only the information that is useful for particular purpose remains

6 0
3 years ago
A wheelbarrow is a good example of a second-class lever. True or False
olganol [36]

Answer:

true

Explanation:

a wheelbarrow has its load situated between the fulcrum and the force the wheel Barrow is 2nd class because of its resistance between the force and the axis

3 0
3 years ago
What is the definition of Rock Strata and Law of Original Horizontality?
timurjin [86]
It's called the <span>Principle of Original Horizontality
</span><span> it just </span>means<span> what it sounds like: that all </span>rock layers <span>were originally horizontal.
</span>Of course, it only applies to sedimentary rocks<span>.
</span>Recall that sedimentary rock is composed of <span> sediments, which are deposited and compacted in one place over time.</span>
3 0
3 years ago
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