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2 years ago

If a sound wave travels 680 m in 2 seconds and has a frequency of 400 hz, what is the wavelength of the wave?

Physics

1 answer:

Kipish [7]2 years ago

5 0

Answer: 0.85 meters (with and without sigfigs)

Explanation: To find the wavelength, you just have to switch around the equation for wave speed: v (wave speed) = λ (wavelength)*f (frequency) so λ (wavelength) = v (wave speed)/f (frequency). You don't have the wave speed but you can calculate it. Since wave speed is measured in meters/second or m/s, you just have to divide the amount of meters you were given by the amount of seconds. You will get 340 m/s. Next, you have to plug the values into the equation: λ (wavelength) = 340 m/s (wave speed)/400 Hz (frequency). The answer is 0.85 meters (seconds cancel) and has the correct number of significant figures.

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mezya [45]

B = 0.018 T Ans,

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F = $\frac{ mv^{2} }{r}$
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And, since a positive charge is moving, it will create magnetic force which is equal to F = qvB
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</span>
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2 years ago

A mass of 5 kg stretches a spring 20 cm. The mass is acted on by an external force of 10 sin t 6 N (newtons) and moves in a medi

nordsb [41]

Answer:

u" + 40u' + 49u = 2 sin(t/6)

upp + 40up + 49u = 2 sin(t/6)

Explanation:

Step 1: Data given

mass = 5 kg

L = 20 cm = 0.2 m

F = 10 sin(t/6)N

Fd(t) = - 6 N

u(0) = 0.03 m/s

u(0) = 0

u'(0) = 3 cm/s

Step 2:

ω =kL

k = ω/L = m*g /L = (5*9.8)/0.2 = 245 kg/s²

Since Fd(t) = -γu'(t) we know:

γ =- Fd(t) / u'(t) = 6N/ 0.03 m/s = 200 Ns/m

The initial value problem which describes the motion of the mass is given by

5u" + 200u' + 245u = 10 sin(t/6) u(0) = 0 ; u'(0) = 0.03

This is equivalent to:

u" + 40u' + 49u = 2 sin(t/6) u(0) = 0 ; u'(0) = 0.03

upp + 40up + 49u = 2 sin(t/6)

With u in m and t in s

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2 years ago

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2 years ago

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