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Harrizon [31]
3 years ago
10

Please help I will mark Brainly !!!

Chemistry
1 answer:
aniked [119]3 years ago
5 0
Low melting and boiling points
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Avogadro’s number in Scientific notation is: 6.02x10^23

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Elements in group 2 are all called alkaline earth metals. What is most similar about the alkaline earth metals?
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N2 + 3H2 - 2NH3
vladimir1956 [14]

The number of mole of nitrogen gas, N₂, needed to produce 150 g of ammonia, NH₃ is 4.41 moles

<h3>How to determine the mole of NH₃ produced </h3>
  • Mass of NH₃ = 150 g
  • Molar mass of NH₃ = 14 + (3×1) = 17 g/mol
  • Mole of NH₃ =?

Mole = mass /molar mass

Mole of NH₃ = 150 / 17

Mole of NH₃ = 8.82 moles

<h3>How to determine the mole of N₂ needed </h3>

Balanced equation

N₂ + 3H₂ —> 2NH₃

From the balanced equation above,

2 moles of NH₃ were produced by 1 mole of N₂.

Therefore,

8.82 moles of NH₃ will be produced by = 8.82 / 2 = 4.41 moles of N₂.

Thus, 4.41 moles of N₂ is  needed for the reaction.

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brainly.com/question/14735801

4 0
2 years ago
PHEASE HELP ASAP
Veronika [31]

Given the balanced chemical equation for combustion of propane:

C_{3}H_{8}+5O_{2}-->3CO_{2}+4H_{2}O

Moles of propane C_{3}H_{8}=3.6 mol

Propane is the limiting reactant as the other reactant oxygen is said to be present in excess.

Amount of products formed would depend on the moles of limiting reactant.

Mole ratio of water to propane as per the balanced chemical equation

                                   =\frac{4molH_{2}O }{1molC_{3}H_{8}}

Calculating the moles of water produced from 3.6 mol propane:

  3.6molC_{3}H_{8}*\frac{4molH_{2}O }{1molC_{3}H_{8}}

                          = 14.4molH_{2}O

Theoretical yield of water = 14.4 mol

Actual yield = 12 mol

Percent yield = \frac{ActualYield}{TheoreticalYield}*100

                      = \frac{12 mol}{14.4 mol}*100=83.3%

6 0
3 years ago
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