The moment of inertia of a uniform solid sphere is equal to 0.448 .
<u>Given the following data:</u>
Mass of sphere = 7 kg.
Radius of sphere = 0.4 meter.
<h3>How to calculate moment of inertia.</h3>Mathematically, the moment of inertia of a solid sphere is given by this formula:
<u>Where:</u>
Substituting the given parameters into the formula, we have;
I = 0.448 .
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Answer:
B = 0.8 T
Explanation:
It is given that,
Radius of circular loop, r = 0.75 m
Current in the loop, I = 3 A
The loop may be rotated about an axis that passes through the center and lies in the plane of the loop.
When the orientation of the normal to the loop with respect to the direction of the magnetic field is 25°, the torque on the coil is 1.8 Nm.
We need to find the magnitude of the uniform magnetic field exerting this torque on the loop. Torque acting on the loop is given by :
B is magnetic field
So, the magnitude of the uniform magnetic field exerting this torque on the loop is 0.8 T.
Answer:
E = 0.437 N/C
Explanation:
Given that,
Charge,
Electric force,
Let the strength of the electric field is E. We know that, the electric force is given by :
F = qE
Where
E is the electric field strength
So, the strength of the electric field is equal to 0.437 N/C.