Answer:
The power in this flow is
Explanation:
Given that,
Distance = 221 m
Power output = 680 MW
Height =150 m
Average flow rate = 650 m³/s
Suppose we need to calculate the power in this flow in watt
We need to calculate the pressure
Using formula of pressure
Where, = density
h = height
g = acceleration due to gravity
Put the value into the formula
We need to calculate the power
Using formula of power
Put the value into the formula
Hence, The power in this flow is
Answer:
The distance can the water be projected is 4.51 m
Explanation:
The speed of the water in the hose is equal to:
v1 = R/A1
If we solve the continuity for v2:
v2 = R/A2 (eq. 1)
The equation for the vertical position is:
yf = yi + vy*t - (1/2)gt²
yi = 0
vy = 0
Clearing t:
(eq. 2)
The equation for position is:
xf = xi + vxt = 0 + v2t = v2t (eq. 3)
Replacing equation 1 and 2 in equation 3:
Answer:
(a) 1.73 s
(b) 14.75 m
(c) 3.36 s
(d) double
(e) 63.32 m
Explanation:
Vertical component of initial velocity, uy = 17 m/s
Horizontal component of initial velocity, ux = 18.3 m/s
(A) At highest point of trajectory, the vertical component of velocity is zero. Let the time taken is t.
Use first equation of motion in vertical direction
vy = uy - gt
0 = 17 - 9.8 t
t = 1.73 seconds
(B) Let the highest point is at height h.
Use III equation of motion in vertical direction
0 = 17 x 17 - 2 x 9.8 x h
h = 14.75 m
(C) The time taken by the ball to return to original level is T.
Use second equation of motion i vertical direction.
h = 0 , u = 17 m/s
0 = 17 t - 0.5 x 9.8 t^2
t = 3.46 second
(D) It is the double of time calculated in part A
(E) Horizontal distance = horizontal velocity x total time
d = 18.3 x 3.46 = 63.32 m
Answer:
The new volume will be 60 liters, so the answer is e) None of these
Explanation:
Charles's Law consists of the relationship between the volume and temperature of a certain amount of ideal gas, which is maintained at a constant pressure, by means of a proportionality constant that is applied directly.
In other words, the Law of Charles establishes that the volume is directly proportional to the temperature of the gas: If the temperature increases, the volume of the gas increases and if instead the temperature of the gas decreases, the volume decreases.
This is mathematically represented by the quotient that exists between volume and temperature, which will have the same value:
Assuming that you have a certain volume of gas V1 that is at a temperature T1 at the beginning of the experiment, if you vary the volume of gas to a new value V2, then the temperature will change to T2, and it will be true:
In this case:
- V1= 20 L
- T1=100 K
- V2= ?
- T2=300 K
Replacing:
Solving:
V2= 60 L
<u><em>The new volume will be 60 liters, so the answer is e) None of these</em></u>