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Vanyuwa [196]
3 years ago
11

A 98.0°C piece of cadmium (c=.850J/g°C) is placed in 150.0g of 37.0°C water. After sitting for a few minutes, both have a temper

ature of 38.6°C. What was the mass of the cadmium sample?
Chemistry
1 answer:
Eduardwww [97]3 years ago
3 0
The answer is 19.9 grams cadmium. 
Assuming there was no heat leaked from the system, the heat q lost by cadmium would be equal to the heat gained by the water:
     heat lost by cadmium = heat gained by the water
     -qcadmium = qwater
Since q is equal to mcΔT, we can now calculate for the mass m of the cadmium sample:
     -qcadmium = qwater
     -(mcadmium)(0.850J/g°C)(38.6°C-98.0°C)) = 150.0g(4.18J/g°C)(38.6°C-37.0°C)
     mcadmium = 19.9 grams
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La tercera ley de Newton dice que cuando dos objetos interactuan, cadan objeto ejerce una fuerza de <u>igual magnitud pero opuesta direccion</u> en el otro.

Ahora veamos como aplicar esto.

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