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mihalych1998 [28]
3 years ago
5

Julius competes in the hammer throw event. the hammer has a mass of 7.26 kg and is 1.215 m long. what is the centripetal force o

n the hammer when it has a tangential speed of 31.95 m/s? the answer is rounded off to the nearest whole number.
Physics
2 answers:
TEA [102]3 years ago
8 0
Centripetal force <span>a force that acts on a body moving in a circular path and is directed toward the center around which the body is moving. It is calculated by the expression:

F = mv^2/r

where m is the mass, v is the velocity and r is the radius.

F = 7.26(31.95)^2 / (1.215) = 6100 N</span>
stepan [7]3 years ago
8 0

Answer:

D. 6,100 N

Explanation:

Correct on edge, :P  

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A 1-kg block is lifted vertically 1 m at constant speed by a boy. The work done by the boy is about:
Igoryamba

Answer:

9.8\; {\rm J}, assuming that the gravitational field strength is g = 9.8\; {\rm N \cdot kg^{-1}}.

Explanation:

Notice that both the speed and the direction of motion of this block are constant. In other words, the velocity of this block is constant.

By Newton's Second Law, the net force on this block would be 0. External forces on this block should be balanced. Thus, the magnitude of the (downward) weight of this block should be equal to the magnitude of the (upward) force that the boy applies on this block.

Let m denote the mass of this block. It is given that m = 1\; {\rm kg}. The weight of this block would be:

\begin{aligned}\text{weight} &= m\, g \\ &= 1\; {\rm kg} \times 9.8\; {\rm N \cdot kg^{-1}} \\ &= 9.8\; {\rm N}\end{aligned}.

Hence, the force that the boy applies on this block would be upward with a magnitude of F = 9.8\; {\rm N}.

The mechanical work that a force did is equal to the product of:

  • the magnitude of the force, and
  • the displacement of the object in the direction of the force.

The displacement of this block (upward by s = 1\; {\rm m}) is in the same direction as the (upward) force that this boy had applied. Thus, the work that this boy had done would be the product of:

  • the magnitude of the force that this boy exerted, F = 9.8\; {\rm N}, and
  • the displacement of this block in the direction, s = 1\; {\rm m}.

\begin{aligned}\text{work} &= F\, s \\ &= 9.8\; {\rm N} \times 1\; {\rm m} \\ &= 9.8\; {\rm J}\end{aligned}.

5 0
2 years ago
Un libro del peso di 12 N è in equilibrio su un tavolo. Sapendo che il coefficiente di attrito statico vale 0,5, la forza di att
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Answer:

60

Explanation:

Translation -

A book weighing 12 N is balanced on a table. Knowing that the static friction coefficient is 0.5, how much is the friction force worth?

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Answer:

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