1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
SCORPION-xisa [38]
3 years ago
14

12) Does the label “centripetal force” ever appear in an FBD?

Physics
1 answer:
Murrr4er [49]3 years ago
6 0
"Though a force, or a resulting sum of forces, may be centripetal, there is not an actual "Centripetal Force" that would appear on an FBD. Since an FBD is a diagram of physical forces at work upon a body, and a centripetal force is not the reaction of some physical object upon another, it would not be proper to show it. You might have a tension force, a weight force, a normal force, electric forces, magnetic forces, or any number of reactions, but actually labeling any of them "centripetal" would be unconventional".
-Yahoo
You might be interested in
When considering the gas laws, the kelvin temperature scale must be used. the reason for this is that the kelvin scale is direct
suter [353]
.;;jmbbbvvb nhjmhnjhmnhjmgmjhyg   gt vfdxg fbrdhtggdfse
7 0
3 years ago
Two identical bullets are used. Both are released at the same height - one fired out of a gun, the other is dropped. Ignoring ai
irina [24]

Answer:

Both bullets will hit the ground at the same time.

Explanation:

Let's only analyze the vertical problem.

Any object that is not in the floor or resting in some site is being affected by the gravitational force (remember that we are ignoring air resistance)

Then the acceleration of this object will be equal to the gravitational acceleration:

a = -9.8m/s^2

Where the minus sign is because this acceleration goes down.

To get the velocity equation we need to integrate over time, we will get:

v(t) = ( -9.8m/s^2)*t + v0

Where v0 is the initial vertical velocity.

To get the position equation we need to integrate over time again, we will get:

p(t) = (1/2)*( -9.8m/s^2)*t^2 + v0*t + H

Where H is the initial height.

p(t) = (-4.9 m/s^2)*t^2 + v0*t + H

The object will hit the ground when p(t) = 0

Then we need to solve for t the next equation:

(-4.9 m/s^2)*t^2 + v0*t + H = 0

Notice that the only things we need to know are:

H = initial height (we know that is the same for both bullets)

v0 = initial vertical velocity (also is the same for both bullets)

Notice that the horizontal velocity does not affect this equation, then we will get the same value of t for the dropped bullet and for the fired bullet.

This means that both bullets will hit the ground at the same time.

8 0
2 years ago
A wire of Nichrome (a nickel– chromium– iron alloy commonly used in heating elements) is 1.0 m long and 1.0 mm² in cross-se
Lyrx [107]

Answer:

The conductivity of Nichrome is 2\times 10^6\ S/m.

Explanation:

Given:

Potential difference (V) = 2.0 V

Current flowing (I) = 4.0 A

Length of wire (L) = 1.0 m

Area of cross section of wire (A) = 1.0 mm² = 1 × 10⁻⁶ m² [1 mm² = 10⁻⁶ m²]

We know, from Ohm's law, that the ratio of voltage and current is always a constant and equal to the resistance of the resistor. Therefore, the resistance of the nichrome wire is given as:

R=\frac{V}{A}=\frac{2.0}{4.0}=0.5\ \Omega

Now, resistance of the nichrome wire in terms of its resistivity, length and area of cross section is given as:

R=\rho\frac{L}{A}

Where, \rho\to resistivity\ of\ Nichrome

Now, plug in all the values given and solve for \rho. This gives,

0.5\ \Omega=\rho\frac{1.0\ m}{1\times 10^{-6}\ m^2}\\\\\rho=\frac{0.5\times 1\times 10^{-6}}{1.0}=0.5\times 10^{-6}\ \Omega-m

Now, conductivity of a material is the reciprocal of its resistivity. Therefore, the conductivity of Nichrome is given as:

\sigma=\frac{1}{\rho}=\frac{1}{0.5\times 10^{-6}}=2\times 10^6\ S/m

Conductivity is measured in Siemens per meter (S/m)

Therefore, the conductivity of Nichrome is 2\times 10^6\ S/m.

7 0
3 years ago
which of the following objects is considered negatively charged A - one with excess electrons on the surface B - one with excess
Ne4ueva [31]
An object that could be considered as negatively charged would be when it has an excess of an electron in its atom. However, when it loses an electron, it could go back to its stable state which is "uncharged" or when there is an excess proton, it could be a positively charged object.
8 0
3 years ago
Which situations describe an elastic collision?
Elan Coil [88]
Elastic collisions<span> are </span>collisions<span> in which both momentum and kinetic energy are conserved. I think the correct answer from the choices listed above is option A. Two </span><span>glass marbles bounce off each other is an example of an elastic collision. Hope this answers the question.</span>
3 0
3 years ago
Read 2 more answers
Other questions:
  • A box slides with uniform acceleration up an incline. The box has an initial speed of 9.0 m/s and rises vertically 2.60 m before
    10·1 answer
  • When a wire with a current is placed in a magnetic field,
    7·1 answer
  • Hi, can anyone write 5 or 4 paragraph about virus pls I rly need it DO NOT PLAGIARIZE!
    13·1 answer
  • You throw a glove straight upward to celebrate a victory. Its initial kinetic energy is K and it reaches a maximum height h. Wha
    10·1 answer
  • Two identical balls move directly toward each other with equal speeds. how will the balls move if they collide and stick togethe
    10·1 answer
  • Does the car traveling the longest time always travel the greatest distance? Why or why not?
    10·1 answer
  • What type of wave is shown below?
    8·1 answer
  • Define uniform and non uniform
    12·2 answers
  • A roller coaster car has 600,00 J of Kinetic energy as it approaches the station to stop. The roller coaster comes to a complete
    7·1 answer
  • A force acts on a body of mass 13 kg initially at restThe force acts for 10 seconds, and once it quits, the body covers 60 m in
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!