What type of foundation do engineers use for a small and light building and when the load of the building is borne by columns? A
1 answer:
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Answer:
efficiency = 0.71999 < 0.78148
efficiency = 0.7999 ≈ 0.78148
Explanation:
given data
Hot reservoir Temp Th = 1350 K
Cold reservoir Temp Tc = 295 K
heat transfer rate = 150,000 kJ/h
solution
first we get here maximum possible efficiency that is express as
maximum possible efficiency = 1 - ..........1
put here value and we get
maximum possible efficiency = 1 -
maximum possible efficiency = 0.78148
and
efficiency = .................2
here Qin = = 41.667
so put here value in equation 2 we get
efficiency =
efficiency = 0.71999 < 0.78148
and
efficiency =
efficiency = 0.7999 ≈ 0.78148
claim might be true or not because there always be looser