Question

A 0.39 percent Carbon hypoeutectoid plain-carbon steel is slowly cooled from 950 oC to a temperature just slightly below 723 oC. Calculate the weight percent proeutectoid ferrite in the steel. Please do not include any numbers after the decimal and give the percentage as "xx" and not "0.xx"

Answer 1

Answer:

53%

Explanation:

To find the weight % in proeutectoid ferrite we use:

Wt % in proeutectoid ferrite=

[(0.80 - 0.39) / (0.80 - 0.02)] * 100=

= (0.41 /0.78) * 100 =

52.56%

which is approximately 53%