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sweet-ann [11.9K]
3 years ago
15

A 0.39 percent Carbon hypoeutectoid plain-carbon steel is slowly cooled from 950 oC to a temperature just slightly below 723 oC.

Calculate the weight percent proeutectoid ferrite in the steel. Please do not include any numbers after the decimal and give the percentage as "xx" and not "0.xx"
Engineering
1 answer:
belka [17]3 years ago
8 0

Answer:

53%

Explanation:

To find the weight % in proeutectoid ferrite we use:

Wt % in proeutectoid ferrite=

[(0.80 - 0.39) / (0.80 - 0.02)] * 100=

= (0.41 /0.78) * 100 =

52.56%

which is approximately 53%

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3 years ago
What is the activation energy (Q) for a vacancy formation if 10 moles of a metal have 2.3 X 10^13 vacancies at 425°C?
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Using the expression shown below as:

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N_v=2.3\times 10^{13}

N = 10 moles

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So,

N = 10\times 6.023\times 10^{23}=6.023\times 10^{24}

Temperature = 425°C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (425 + 273.15) K = 698.15 K  

T = 698.15 K

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2.3\times 10^{13}=6.023\times 10^{24}\times e^{-\frac {Q_v}{1.38\times 10^{-23}\times 698.15}

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4 0
3 years ago
A slender rod AB, of weight W, is attached to blocks A and B, which move freely in the guides shown. The blocks are connected by
gregori [183]

Answer:

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(a) The equation for tension (T) can be derived by considering the summation of moment in the clockwise direction. Thus:

Summation of moment in clockwise direction is equivalent to zero. Therefore,

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8 0
2 years ago
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