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nordsb [41]
3 years ago
11

A train on a straight track goes in the positive direction for 5.2 km, and then backed up for 3.3 km. Which of the following des

cribes a distance covered by the train?
Physics
1 answer:
ivann1987 [24]3 years ago
5 0

Answer:

Total distance = 8.5 km

Explanation:

The question needs options for it to be answered properly. However, you should take note of the following explanation.

Distance is a scalar quantity and as such, it does not consider the object direction.

Having said that, the total distance moved by the train is calculated by adding up the distance moved in all directions.

i.e.

Total Distance = 5.2 km + 3.3 km

Total Distance = 8.5 km

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A 2.5-kg rock is dropped off a 32-m cliff and hits a spring, compressing it 57 cm. What is the spring constant? Round your answe
n200080 [17]

Answer: 4800 N/m

Explanation:

Given

mass of rock m=2.5\ kg

Height of cliff h=32\ m

compression in the spring x=57\ cm

Here, potential energy is converted into kinetic energy which in turn converts to elastic potential energy of the spring

\Rightarrow mgh=\dfrac{1}{2}kx^2\\\\\Rightarrow k=\dfrac{2mgh}{x^2}\\\\\Rightarrow k=\dfrac{1568}{0.3249}\\\\\Rightarrow k=4826.100\approx 4800\ N/m

6 0
3 years ago
Read 2 more answers
A box is at rest and a force of 250N is applied to it.If the frictional force is 200N determine the net force
nadya68 [22]

Answer:

50N

Explanation:

the net force is the addition of all forces in an object.

The frictional force is the opposite of the applied force, so:

Nf(net force)= 250(applied force)-200(frictional force)

so Nf=50N

3 0
3 years ago
Be sure to answer all parts. Consider the following energy levels of a hypothetical atom: E4 −2.01 × 10−19 J E3 −5.71 × 10−19 J
pashok25 [27]

(a) 159 nm

First of all, let's calculate the energy difference between the level E1 and E4:

\Delta E=E_4 -E_1 = -2.01\cdot 10^{-19}J-(-1.45\cdot 10^{-18} J)=1.25\cdot 10^{-18} J

Now we know that this energy difference is related to the wavelength of the absorbed photon by

\Delta E=\frac{hc}{\lambda}

where

h=6.63\cdot 10^{-34} Js is the Planck constant

c=3\cdot 10^8 m/s is the speed of light

\lambda is the wavelength of the photon

Solving for \lambda, we find

\lambda=\frac{hc}{\Delta E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{1.25\cdot 10^{-18} J}=1.59\cdot 10^{-7} m = 159 nm

b) 293 nm

As done in part a), let's calculate the energy difference between the level E2 and E3:

\Delta E=E_3 -E_2 = -5.71\cdot 10^{-19}J-(-1.25\cdot 10^{-18} J)=6.79\cdot 10^{-19} J

this energy difference is related to the wavelength of the absorbed photon by

\Delta E=\frac{hc}{\lambda}

Solving for \lambda again, we find

\lambda=\frac{hc}{\Delta E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{6.79\cdot 10^{-18} J}=2.93\cdot 10^{-7} m = 293 nm

c) 226 nm

As done in part a) and b), let's calculate the energy difference between the level E1 and E3:

\Delta E=E_3 -E_1 = -5.71\cdot 10^{-19}J-(-1.45\cdot 10^{-18} J)=8.79\cdot 10^{-19} J

this energy difference is related to the wavelength of the emitted photon by

\Delta E=\frac{hc}{\lambda}

Solving for \lambda again, we find

\lambda=\frac{hc}{\Delta E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{8.79\cdot 10^{-18} J}=2.26\cdot 10^{-7} m = 226 nm

4 0
3 years ago
Using Newton's third law of motion, write a scientific explanation that describes why
Aneli [31]

Answer:

when a force is applied by one object to a second object, an equal and opposite force is applied back on the first object

Explanation:

4 0
2 years ago
From the small number of impact craters on ____, planetary geologists suspect that virtually all its original surface has been c
allsm [11]

<span>From the small number of impact craters on moon, planetary geologists suspect that virtually all its original surface has been covered over by younger volcanic activity</span>. Most of the Moon's surface is densely covered with craters, but we find relatively few craters within the lunar maria.<span> </span>

3 0
4 years ago
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