A meter stick is found to balance at the 49.7-cm mark when placed on a fulcrum. When a 65.5-gram mass is attached at the 21.0-cm
1 answer:
Answer:
113.53 g
Explanation:
Please see attached photo for explanation.
In the attached photo, M is the mass of the meter stick.
The value of M can be obtained as shown below:
Clockwise moment = M × 10.5
Anticlockwise moment = 65.5 × 18.2
Anticlockwise moment = Clockwise moment
65.5 × 18.2 = M × 10.5
1192.1 = M × 10.5
Divide both side by 10.5
M = 1192.1 / 10.5
M = 113.53 g
Thus, the mass of the meter stick is 113.53 g
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Answer:
The answer would be 420 m/s
Explanation:
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I Hope this Helps!!!
By equation of motion we have v = u + at
Where u = Initial velocity, v = final velocity, t = time taken and a = acceleration
Here v = 141 m/s, u = 17.7 m/s and t = 6 s
On substitution we will get
141 = 17.7+ 6a
So, a = (141-17.7)/6 = 20. 55 m/
Aceeleration = 20. 55 m/ along north direction.