A meter stick is found to balance at the 49.7-cm mark when placed on a fulcrum. When a 65.5-gram mass is attached at the 21.0-cm
1 answer:
Answer:
113.53 g
Explanation:
Please see attached photo for explanation.
In the attached photo, M is the mass of the meter stick.
The value of M can be obtained as shown below:
Clockwise moment = M × 10.5
Anticlockwise moment = 65.5 × 18.2
Anticlockwise moment = Clockwise moment
65.5 × 18.2 = M × 10.5
1192.1 = M × 10.5
Divide both side by 10.5
M = 1192.1 / 10.5
M = 113.53 g
Thus, the mass of the meter stick is 113.53 g
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Answer:
a)
b)
c)
d)
Explanation:
Given:
- mass of the astronaut,
- vertical displacement of the astronaut,
- acceleration of the astronaut while the lift,
a)
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Here the lift force is the resultant of the force of gravity being overcome by the force of helicopter.
where:
force by the helicopter
force of gravity
b)
The gravitational force on the astronaut:
d)
Since the astronaut has been picked from an ocean we assume her initial velocity to be zero,
using equation of motion:
c)
Hence the kinetic energy: