A meter stick is found to balance at the 49.7-cm mark when placed on a fulcrum. When a 65.5-gram mass is attached at the 21.0-cm
1 answer:
Answer:
113.53 g
Explanation:
Please see attached photo for explanation.
In the attached photo, M is the mass of the meter stick.
The value of M can be obtained as shown below:
Clockwise moment = M × 10.5
Anticlockwise moment = 65.5 × 18.2
Anticlockwise moment = Clockwise moment
65.5 × 18.2 = M × 10.5
1192.1 = M × 10.5
Divide both side by 10.5
M = 1192.1 / 10.5
M = 113.53 g
Thus, the mass of the meter stick is 113.53 g
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Answer:
a) 66.4 relative to the west in the south-west direction
b) 5.455 hours
Explanation:
a)If the wind is blowing east-ward at a speed of 40km/h, then the west component of the geese velocity must be 40km/h in order to counter balance it. Geese should be flying south-west at an angle of
relative to the West
b) The south-component of the geese velocity is
The time it would take for the geese to cover 500km at this rate is
t = 500 / 91.65 = 5.455 hours
Answer:
Explanation:
The angular momentum of that same disk-sphere remains unchanged the very same way before and after the impact of the collision when the clay sphere adheres to the disk.
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The overall value of such moment of inertia is now altered when the clay spherical sticks. Due to the inclusion of the clay sphere, the moment of inertia will essentially rise. As a result of this increase, the angular speed w decreases in value.
Recall that:
The Kinetic energy is given by:
where;
is constant and w reduces;
As a result, just after the collision, the system's total kinetic energy decreases.
- So as the index of refraction value increases, the optical density increases, and the speed of light in that material decreases.