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Brrunno [24]
4 years ago
12

How does newtons laws apply to the egg drop experiment

Physics
1 answer:
Anon25 [30]4 years ago
5 0
Because an object in rest stays in rest until an unequal force pushes it so gravity is pushing on the egg making it drop
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In a distance -time graph: What type of motion does a curved line represent?​
Semmy [17]

Answer: If the speed of an object changes, it will be accelerating or decelerating . This can be shown as a curved line on a distance-time graph.

Explanation:

6 0
3 years ago
Motor oil, with a viscosity of 0.25 N ∙ s/m2, is flowing through a tube that has a radius of 3.0 mm and is 1.0 m long. The drop
Alex73 [517]

Answer:

The average speed of the oil is 1 m/s.

Explanation:

Given that,

Viscosity \eta= 0.25 N-s/m^2

Radius r = 3.0 mm

Length = 1.0 m

Pressure = 200 kPa

We need to calculate the average speed of the oil

Using formula of pressure

\Delta P=\dfrac{8\pi\eta\rho v}{A}

v=\dfrac{A\times\Delta P}{8\pi\eta\rho}

Where, A = area

\rho = density of oil

\eta = viscosity

Put the value into the formula

v=\dfrac{\pi\times(3.0\times10^{-3})^2\times200\times10^{3}}{8\pi\times0.25\times0.9}

v=1\ m/s

Hence, The average speed of the oil is 1 m/s.

6 0
4 years ago
the density of dead sea surface water is about 1.166 g/ml. how much mass, in grams, would 2 liters of this salty water have?
kogti [31]
<span>Density is a value for mass, such as kg, divided by a value for volume, such as m^3. Density is a physical property of a substance that represents the mass of that substance per unit volume. The mass of the salty water is calculated as follows:

Mass = 1.166 g/mL ( 2000 mL ) = 2332 g of salty water</span>
6 0
3 years ago
Read 2 more answers
The more domains that are aligned in a magnet ___________.
I am Lyosha [343]
Hey, Sissy05pooh!
The more domains that are aligned in a magnet it is stronger, and the magnetic field is larger.
6 0
3 years ago
A rocket accelerates at 25m/s^2 for 5s before it runs out of fuel and dies. What is the maximum height reached by the rocket?
sineoko [7]

Answer:

1109m

Explanation:

The distance h₁ traveled by the rocket during acceleration:

h_1=\frac{1}{2}at^2

The velocity v₁ at this height h₁:

v_1=at

When the rocket runs out of fuel, energy is conserved:

E=\frac{1}{2}mv_1^2+mgh_1=mgh_2

Solving for h₂:

h_2=\frac{v_1^2}{2g}+h_1=\frac{(at)^2}{2g}+\frac{1}{2}at^2

8 0
3 years ago
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