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vitfil [10]
4 years ago
11

Predict all bond angles in the following compound. Be sure to answer all parts. HCa≡CbCcH2OH

Chemistry
1 answer:
morpeh [17]4 years ago
6 0

Answer:

See explanation below

Explanation:

What we have to consider is the hybridation of the three carbon atoms we are asked  in this question .

Hybridization   # bonds                            Angle

sp³                         4                                   109.5º

sp²                         3 +   1 pi bond              120º

sp                           2 + 2 pi bonds             180º

Carbon atom (a) is bonded to two atoms: Carbon (b) and one Hydrogen. It has a triple bond to Carbon (b). Therefore its hybridization is sp with two pi bonds, and for sp hybridization we know the angle is 180 º.

The same hybridization sp happens to carbon (b) bonded to Carbon (c) and C(a) using one sp bond to Carbon (a) and 2 pi bonds; it is also bonded using the other sp  to Carbon (c). The angle is therefore 180 between Carbons b and c.

Carbon C is bonded to 4 atoms, therefore, its hybridization is sp³ and the angles with these 4 atoms will be 109.5 º tehedral  ( one bond to OH, one to C(b), and 2 to H ) .

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Vaselesa [24]

Answer:

2. V_2=17L

3. V=82.9L

Explanation:

Hello there!

2. In this case, we can evidence the problem by which volume and temperature are involved, so the Charles' law is applied to:

\frac{V_2}{T_2}=\frac{V_1}{T_1}

Thus, considering the temperatures in kelvins and solving for the final volume, V2, we obtain:

V_2=\frac{V_1T_2}{T_1}

Therefore, we plug in the given data to obtain:

V_2=\frac{18.2L(22+273)K}{(45+273)K} \\\\V_2=17L

3. In this case, it is possible to realize that the 3.7 moles of neon gas are at 273 K and 1 atm according to the STP conditions; in such a way, considering the ideal gas law (PV=nRT), we can solve for the volume as shown below:

V=\frac{nRT}{P}

Therefore, we plug in the data to obtain:

V=\frac{3.7mol*0.08206\frac{atm*L}{mol*K}*273.15K}{1atm}\\\\V=82.9L

Best regards!

6 0
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