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Ostrovityanka [42]
4 years ago
15

The specific heat of gold is 0.031 calories/gram°C. If 10.0 grams of gold were heated and the temperature of the sample changed

by 20.0°C, how many calories of heat energy were absorbed by the sample?
6.2 calories
0.016 calories
6,451 calories
0.062 calories
Chemistry
2 answers:
kramer4 years ago
6 0
I believe the correct answer here is 6.2. Since you would have to multiply the specific heat of gold by the amount of gold by the new heat of the gold. So this would be:

0.031 x 10 x 20 = 6.2
eimsori [14]4 years ago
3 0
The answer is A. 6.2 calories
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Answer:

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The electron configuration for Boron can be written with the first two electrons in the 1s orbital. Since 1s orbital can hold only two electrons, out of the remaining three electrons; two electrons will go in the 2s orbital. The remaining one electron in the 2p orbital. Therefore the Boron electron configuration will be 1s^2 2s^2 2p^1

Since 1s^2 is the electron configuration for Helium, Electron configuration for Boron can also be written as [He] 2s^2 2p^1

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3 years ago
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zloy xaker [14]

Answer:

V₂ = 28 mL

Explanation:

Given data:

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Solution:

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Mathematical expression:

V₁/T₁ = V₂/T₂

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T₁ = Initial temperature

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V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

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