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Nana76 [90]
3 years ago
11

Pay it forward! Answer a questio1) For a positive point charge, the lines radiate ………. . While, for a negative point charge, the

lines converge …………. .
2) The magnitude of the electric force between two protons is 2.3 X 10-26 N. Where ke = 9 X 109 N.m2/C, e = 1.6 X 10-19 C. How far apart are they? ………… m
3) The unit of the electric field is ………….
n while you wait for yours!
Physics
1 answer:
nikitadnepr [17]3 years ago
7 0

Explanation:

1) For a positive point charge, the lines radiate outwards

for a negative point charge, the lines converge inwards

2) F = 2.3 X 10^-26 N

k = 9 X 10^9 N.m²/C

q1 = q2 = e = 1.6 X 10^-19 C

r = ?

F = kq1q2/r²

r² = kq1q2/F

r = √[kq1q2/F ]

r = √0.0100

r = 0.10m

The two protons are 0.10 m apart

3) The unit if electric field intensity is Newton-per-coulomb N/C

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3 years ago
A 200-Ω resistor is connected in series with a 10-µF capacitor and a 60-Hz, 120-V (rms) line voltage. If electrical energy costs
Vika [28.1K]

Answer:

Cost to leave this circuit connected for 24 hours is $ 3.12.

Explanation:

We know that,

\mathrm{X}_{\mathrm{c}}=\frac{1}{2 \pi \mathrm{fc}}

f = frequency (60 Hz)

c= capacitor (10 µF = 10^-6)  

\mathrm{X}_{\mathrm{c}}=\text { Capacitive reactance }

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\mathrm{X}_{\mathrm{c}}=\frac{1}{2 \times 3.14 \times 10 \times 10^{-6} \times 60}

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Energy used in 54 hours = 26 × 24 = 624 watt hours

E = 0.624 kilowatt hours

Cost = (5)(0.624) = 3.12  

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