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BlackZzzverrR [31]
2 years ago
12

Why is it important to assess flexibility both before and during a workout regimen? a. to assess flexibility progress b. to keep

muscles warm c. to establish flexibility baselines d. none of the above please select the best answer from the choices provided. a b c d
Physics
2 answers:
Inga [223]2 years ago
8 0

Answer:

A

Explanation:

lidiya [134]2 years ago
5 0

It important to assess flexibility both before and during a workout regimen because to assess flexibility progress.

<h3>What is a flexibility exercise?</h3>

Flexibility exercises, as the name implies, help to increase the stretch of the muscles, improving the range of motion. More flexibility is also important to help prevent possible post-workout soreness.

In this case we have that the reason to continue doing stretching before and during the exercises is about  to assess flexibility progress.

See more about flexibility at brainly.com/question/15395713

#SPJ4

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Why are sunlight and gravity not considered matter?
Nady [450]

Sunlight and gravity are not considered matter because sunlight does not have  a rest mass that is characteristic of matter while gravity is just a vector component of matter.

<u>Explanation:</u>

Sunlight has energy and momentum that makes it similar to matter but it cannot be considered matter when you consider all the factors that are characteristic of matter. Light is an electromagnetic wave that is made up of photons and  the protons do not have rest mass.

Gravity is  a vector component of matter that has both magnitude as well as direction and the gravity increases with increase in mass of an object.

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3 years ago
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A book is sitting on a shelf. Unless someone picks it up or something knocks it off, it will continue to sit there. This is beca
olga_2 [115]
Newton's 1st law of Motion

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3 years ago
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Two long, straight parallel wires are placed 38 cm apart, one above the other. The top and bottom wires are carrying currents 4.
ElenaW [278]

Answer:

The force per unit length (N/m) on the top wire is 16.842 N/m

Explanation:

Given;

distance between the two parallel wire, d = 38 cm = 0.38 m

current in the first wire, I₁ = 4.0 kA

current in the second wire, I₂ = 8.0 kA

Force per unit length, between two parallel wires is given as;

\frac{F}{L} = \frac{\mu_oI_1I_2 }{2\pi d }

where;

μ₀ is constant = 4π x 10⁻⁷ T.m/A

Substitute the given values in the above equation and calculate the force per unit length

\frac{F}{L} = \frac{\mu_oI_1I_2 }{2\pi d } = \frac{4\pi *10^{-7}*4000*8000 }{2\pi *0.38} = 16.842 \ N/m

Therefore, the force per unit length (N/m) on the top wire is 16.842 N/m

4 0
3 years ago
Help please! this is physics !
KATRIN_1 [288]

Answer:

4. The choose b. 0.000355

Ans; 3.55× 10-⁴ = 0.000355

5. The choose C. 80600

Ans; 8.06 ×10⁴= 806×10² = 80600

I hope I helped you^_^

4 0
3 years ago
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?/1 Jorge traveled 5 miles north to school. He then traveled 3 miles west to the store. Then he left the store and traveled 5 mi
aleksklad [387]

Answer:

He's 3 miles west of school.

Explanation:

He went 5 miles up and 5 miles down which means that he really didn't go up or down.  In between that, he went 3 miles west so if the 5 milers don't count, this puts him at 3 miles west of school.

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3 years ago
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